If s is the side of the square base, the area of the square base is s^2.
The volume of the square base is,
V = (s²) (h)
s² = V/h
s² = 3n³ + 13n² + 16n + 4 / <span>3n + 1
You can do this division by factoring, synthetic division, or by plain division.
Factoring out 3n + 1 from the numerator gives you:
</span>s² = (3n + 1)(n² + 4n + 4) / 3n+1
s² = n² + 4n + 4
Therefore, the area of the square base is <span>n² + 4n + 4.</span>
did u ever get the answers
Here you have 2 linear equations and are to solve this system. Both equations have already been solved for y, so you can set one of them = to the other one:
-2x+11 = -3x+21.
Then 3x-2x = 21 - 11, or x = 10 (answer)
Find y by subst. x = 10 into either of the given equations.
Solution is then (10, ? )
Answer:
125
Step-by-step explanation:
5^3 = 5 x 5 x 5
5 x 5 x 5 = 25 x 5
25 x 5 = 125
