A board 83 inches long is to be cut into three pieces for framing. The longest piece must be twice the length of the middle-size
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Answer:
<h2><em>29.4 length and 21.4 width.</em></h2>Step-by-step explanation:
To fin the dimensions of the pool we need to use the total area of the pool plus the concrete walkway. Lets say that <em>W </em>is the width and <em>L </em>the length. We know that, the walkway has 3 ft wide, this means that the width and length are increased by 6ft (3ft on each side). So, the total area can be expressed like this: .
In addition, we know that the total area is 970 and the length is 8 ft longer than the width (). So:
With this quadratic equation we're gonna have to solution, the most reasonable is part of the answer. So, solving the equation we have as solutions: and
Therefore, the width is 21.4 ft, because the negative number cannot represent distances.
Using the relation between length and width:
<em>Therefore, the dimensions of the pool are 29.4 length and 21.4 width.</em>
We substitute the given into the equation
given: a=-1, b=2, c=
=(
-1
=
-1
=
-1
=
-1
to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:
=-2.5
Equation=-2.5-1=-3.5
OR Common Denominator:
=
×
(denominator should be -2=common)
=+
=
which also = to -3.5
given: a=-1, b=2, c=
=(
=
=
=
to continue, we can either find a common denominator or change the fraction to decimal.
Fraction to Decimal:
Equation=-2.5-1=-3.5
OR Common Denominator:
=
=
=
which also = to -3.5