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1 year ago

14

Does someone mind helping me with this problem? Thank you!

1 answer:

lesya [120]1 year ago

6 0

Answer:

the answer is 10,000

Step-by-step explanation:

i don't know

I think you do this

how many numbers times itself to the length of the code.

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Arithmetic and geometric sequence<br> An=-9.2+(n-1)2.1

bazaltina [42]

Answer:

Your input -2.9,-5.0,-7.1,-9.2,-11.3,-13.4,-15.5,-17.6 appears to be an arithmetic sequence

Step-by-step explanation:

3 0

2 years ago

Determine whether the sequence converges or diverges. If it converges, find the limit. (If an answer does not exist, enter DNE.)

In-s [12.5K]

Answer:

The sequence diverges.

Step-by-step explanation:

A sequence $a_{n}$ converges when $\lim_{n \rightarrow \infty} a_{n}$ is a real number.

In this question, the sequence given is:

$a_{n} = 4n\cos{(7n\pi)}$

The cosine is always going to be between -1 and 1, so for the convergence of the sequence, we look it as: $a_{n} = 4n$ . So

$\lim_{n \rightarrow \infty} a_{n} = \lim_{n \rightarrow \infty} 4n = \infty$

Since the limit is not a real number, the sequence diverges.

5 0

2 years ago

Find the arc length of the given curve between the specified points. x = y^4/16 + 1/2y^2 from (9/16), 1) to (9/8, 2).

lutik1710 [3]

Answer:

The arc length is $\dfrac{21}{16}$

Step-by-step explanation:

Given that,

The given curve between the specified points is

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

The points from $(\dfrac{9}{16},1)$ to $(\dfrac{9}{8},2)$

We need to calculate the value of $\dfrac{dx}{dy}$

Using given equation

$x=\dfrac{y^4}{16}+\dfrac{1}{2y^2}$

On differentiating w.r.to y

$\dfrac{dx}{dy}=\dfrac{d}{dy}(\dfrac{y^2}{16}+\dfrac{1}{2y^2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}\dfrac{d}{dy}(y^4)+\dfrac{1}{2}\dfrac{d}{dy}(y^{-2})$

$\dfrac{dx}{dy}=\dfrac{1}{16}(4y^{3})+\dfrac{1}{2}(-2y^{-3})$

$\dfrac{dx}{dy}=\dfrac{y^3}{4}-y^{-3}$

We need to calculate the arc length

Using formula of arc length

$L=\int_{a}^{b}{\sqrt{1+(\dfrac{dx}{dy})^2}dy}$

Put the value into the formula

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4}-y^{-3})^2}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-2\times\dfrac{y^3}{4}\times y^{-3}}dy}$

$L=\int_{1}^{2}{\sqrt{1+(\dfrac{y^3}{4})^2+(y^{-3})^2-\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4})^2+(y^{-3})^2+\dfrac{1}{2}}dy}$

$L=\int_{1}^{2}{\sqrt{(\dfrac{y^3}{4}+y^{-3})^2}dy}$

$L= \int_{1}^{2}{(\dfrac{y^3}{4}+y^{-3})dy}$

$L=(\dfrac{y^{3+1}}{4\times4}+\dfrac{y^{-3+1}}{-3+1})_{1}^{2}$

$L=(\dfrac{y^4}{16}+\dfrac{y^{-2}}{-2})_{1}^{2}$

Put the limits

$L=(\dfrac{2^4}{16}+\dfrac{2^{-2}}{-2}-\dfrac{1^4}{16}-\dfrac{(1)^{-2}}{-2})$

$L=\dfrac{21}{16}$

Hence, The arc length is $\dfrac{21}{16}$

6 0

2 years ago

jacks car used 18 gallons of gasoline to go 468 miles. At that rate, how many gallons would be used to go 754 miles? Explain you

matrenka [14]

Well if you take 468 and divide it by 18 you get 26 that 26mpg take 754 divide it by 26 and you get 29 and that's how many gallons he used

6 0

2 years ago

Read 2 more answers

Can someone help me please

Lisa [10]

Answer:

perimeter is 12x-6

Step-by-step explanation:

perimeter is the sum of all sides

3(x+2) + 2x+11 + 7x-23

distribute the 3 in the first term, then combine 'like terms'

3x+6 + 2x+11 + 7x-23

3x+2x+7x + 6+11+(-23)

12x-6

4 0

1 year ago

Read 2 more answers