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Zigmanuir [339]
3 years ago
10

Endosymbiotic theory in chronological order

Biology
1 answer:
natka813 [3]3 years ago
6 0

Answer:The endosymbiotic theory states that some of the organelles in eukaryotic cells were once prokaryotic microbes.

Chronological order is a way of arranging actions, events or things according to the time they occurred. It is demonstrated by showing what happened first, what went on next, what came about in the succeeding occurrences,

Explanation:

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How long would it take
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Solution:
4.2 x 10^6 bp/10^3 bp/seconds         = 4.2 + 103 s which is 4200 seconds and equivalents to 70 minutes

In addition, assuming a pause of 2 seconds for re initiating after completing every okazaki fragment and assuming the okazaki fragments average 1000 nucleotide long.  
4.2 x 10^6 bp/10^3 bp                        = 4200 okazaki fragments                           4200 * 2 seconds                               = 8400 seconds which is 140 minutes or 2 hours 20 minutes of pauses alone.                                                                        

Therefore, overall time would be pauses plus the 70 minutes so total time of 210 minutes. Assuming that the replisome completely disassociates from the DNA after every okazaki fragment and must spend one-minute rebinding.

4200 okazaki fragments. 60 seconds rebinding time per fragment:                        4200 x 1 minute = 4200 minutes rebinding time plus 70 minutes for actual replication. 4200 minutes is 70 hours which is almost 3 days. 
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