Answer:
A. ![150^{\circ}](https://tex.z-dn.net/?f=150%5E%7B%5Ccirc%7D)
Step-by-step explanation:
We have been given image of two parallel lines r and s cut by a transversal t. We are asked to find the measure of angle 1.
We can see from our given diagram that the angle that measures 30 degrees is corresponding angle to the supplementary angle of 1. So angle that measures 30 degrees will be supplementary angle of angle 1.
Since supplementary angles add up-to 180 degrees, so we can set an equation as:
![m\angle 1+30^{\circ}=180^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%201%2B30%5E%7B%5Ccirc%7D%3D180%5E%7B%5Ccirc%7D)
![m\angle 1+30^{\circ}-30^{\circ}=180^{\circ}-30^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%201%2B30%5E%7B%5Ccirc%7D-30%5E%7B%5Ccirc%7D%3D180%5E%7B%5Ccirc%7D-30%5E%7B%5Ccirc%7D)
![m\angle 1=150^{\circ}](https://tex.z-dn.net/?f=m%5Cangle%201%3D150%5E%7B%5Ccirc%7D)
Therefore, the measure of angle 1 is 150 degrees and option A is the correct choice.
The following information will help us with this problem:
![\sqrt[m]{x^n} = x^{\frac{n}{m}](https://tex.z-dn.net/?f=%5Csqrt%5Bm%5D%7Bx%5En%7D%20%3D%20x%5E%7B%5Cfrac%7Bn%7D%7Bm%7D)
When we use that information in the context of this problem, we can find:
![\sqrt[4]{15^7} = 15^{\frac{7}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B15%5E7%7D%20%3D%2015%5E%7B%5Cfrac%7B7%7D%7B4%7D%7D)
Thus, a = 15, b = 7, and c = 4.
Answer:
multiply across
Step-by-step explanation:
3/1 × 1/7 = 3/7
Answer:
x = -3
Step-by-step explanation:
<em>I hope you mean "no solution" as in 'equal to zero' because that's what I'm doing and what makes sense.</em>
<em>Start by setting the equation equal to zero.</em>
3x + 9 = 0
<em>Subtract the </em><em>9</em><em> from both sides to move it to the right side.</em>
3x = -9
<em>Divide the </em><em>3</em><em> from both sides to isolate the </em><em>x.</em>
x = -3
<em>We can check that </em><em>x = -3</em><em> is the correct answer by plugging it in and seeing if it equals </em><em>zero</em><em>.</em>
3(-3) + 9
-9 + 9
0
To get back on track on start off good with the new year