wheee
Compute each option
option A: simple interest
simple interest is easy
A=I+P
A=Final amount
I=interest
P=principal (amount initially put in)
and I=PRT
P=principal
R=rate in decimal
T=time in years
so given
P=15000
R=3.2% or 0.032 in deecimal form
T=10
A=I+P
A=PRT+P
A=(15000)(0.032)(10)+15000
A=4800+15000
A=19800
Simple interst pays $19,800 in 10 years
Option B: compound interest
for interest compounded yearly, the formula is
where A=final amount
P=principal
r=rate in decimal form
t=time in years
given
P=15000
r=4.1% or 0.041
t=10
use your calculator
A=22418.0872024
so after 10 years, she will have $22,418.09 in the compounded interest account
in 10 years, the investment in the simple interest account will be worth $19,800 and the investment in the compounded interest account will be worth$22,418.09
Answer:
You have 44$, your brother has 11$.
Step-by-step explanation:
Let 
be the amount of money your brother has.
Since you have four times the amount of money your brother has, we can call the amount of money you have 
.
Thus, you have:
Answer:
A.) gf(x) = 3x^2 + 12x + 9
B.) g'(x) = 2
Step-by-step explanation:
A.) The two given functions are:
f(x) = (x + 2)^2 and g(x) = 3(x - 1)
Open the bracket of the two functions
f(x) = (x + 2)^2
f(x) = x^2 + 2x + 2x + 4
f(x) = x^2 + 4x + 4
and
g(x) = 3(x - 1)
g(x) = 3x - 3
To find gf(x), substitute f(x) for x in g(x)
gf(x) = 3( x^2 + 4x + 4 ) - 3
gf(x) = 3x^2 + 12x + 12 - 3
gf(x) = 3x^2 + 12x + 9
Where
a = 3, b = 12, c = 9
B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)
To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula
Y = 3x + 3
X = 3y + 3
Make y the subject of formula
3y = x - 3
Y = x/3 - 3/3
Y = x/3 - 1
Therefore, g'(x) = x/3 - 1
For g'(12), substitute 12 for x in g' (x)
g'(x) = 12/4 - 1
g'(x) = 3 - 1
g'(x) = 2.
9 on the top as well so 9 x 2 18 3x2 6 3
