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4 years ago

Easy math show work multiple choice please help me Find the volume of a cylinder

Mathematics

1 answer:

tia_tia [17]4 years ago

7 0

Answer: $\pi (6)(6)(20)$

Step-by-step explanation: v= $\pi r^{2} h$

V=3.14*6^2*20

V= 2261.95

Or $\pi (6)(6)(20)$

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How do I find the sides of a right triangle using sine, cos, or tan, with only the three angles and the hypotenuse

Yuki888 [10]

In this right triangle, you are given the measurements for the hypotenuse, c, and one leg, b. The hypotenuse is always opposite the right angle and it is always the longest side of the triangle. To find the length of leg a, substitute the known values into the Pythagorean Theorem. Solve for a2.

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3 years ago

Six of 16 students in Mr. McConney's class are serving detentions, the rest are here for tutoring. What percent of students are

Ivan

Answer:

62.5%

Step-by-step explanation:

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3 years ago

Read 2 more answers

Can someone pls help me answer this :/

eimsori [14]

Answer:

y = - $\frac{3}{2}$ x + 6

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + b ( m is the slope and b the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, 6) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = $\frac{0-6}{4-0}$ = $\frac{-6}{4}$ = - $\frac{3}{2}$

Since the line crosses the y- axis at (0, 6) ⇒ b = 6

y = - $\frac{3}{2}$ x + 6 ← equation of line

5 0

3 years ago

Graphing system of equations: y=5x+2 and y=-x+8

Harman [31]

Red - y=5x+2
blue - y=-x+8

4 0

3 years ago

A vertical lamppost of height 6 m is at P When Sam stands at the point A. the shadow formed is 2.1 m long. When Sam stands at th

Damm [24]

Step-by-step explanation:

triangle ADA' and OPA' are similar so, using property of similar triangles :

6/AD = (13.3+3.6-PB'+2.1)/2.1

{A'P = 13.3 +3.6 - PB' + 2.1}

6/AD = (16.9-PB'+2.1)/2.1

6/AD = (19-PB')/2.1 - EQN I

As we know, AD = BC as both of them are Sam's height (constant)

triangle OPB' and BCB' are similar so, using property of similar triangles:

6/BC = PB'/3.6

OR, 6/AD = PB'/3.6 (AD = BC) - EQN II

Now,

comparing EQN I AND II we get :

(19-PB')/2.1 = PB'/3.6

or, 68.4 - 3.6PB' = 2.1PB'

or, 68.4 = 5.7PB'

so, PB' = 12 m

Now, as we know,

6/BC = PB'/3.6

OR, 6/BC = 12/3.6

OR, (6×3.6)/12 = BC

So, the height of Sam is 1.8 m.

tanA' = AD/AA'

<A' = tan‐¹(1.8/2.1)

<B' = tan‐¹(1.8/3.6)

Now,

<A'OB' = 180 - tan‐¹(1.8/2.1) - tan‐¹(1.8/3.6)

<A'OB' = 112.833

7 0

2 years ago