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Anna35 [415]
4 years ago
6

A man weighing 80 kg gets into an elevator. The elevator starts moving upward with an acceleration of 2 m/s2. What is the reacti

on force exerted by the floor of the elevator on the man? A) 388 N B) 624 N C) 763 N D) 944 N
Mathematics
1 answer:
maria [59]4 years ago
3 0

The reaction force exerted by the floor of the elevator on the man is D.944 N

Step-by-step explanation:

When the elevator is accelerating upwards at 2 m/s² there occurs a fictitious force acting downwards to produce a downward acceleration of 2 m/s².

The formula to apply here is ;

Weight due to gravity=mg where m is mass of the man and g is acceleration due to gravity.

Due to additional downward acceleration the total acceleration downwards will be : 9.8+2 = 11.8 m/s²

The man weighs down on the elevator floor with a force of ;

F=m(a+g) where m is mass of man, a is acceleration

F=80( 9.8+2)

F=80(11.8)= 944 N

The reaction force by the floor of the elevator is thus 944 N

Learn More

Elevator physics :brainly.com/question/13464055

Keywords : elevator, acceleration, moving upwards, reaction force, floor

#LearnwithBrainly

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AleksAgata [21]

Answer:

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Step-by-step explanation

well at least thats my guess!

we have to go by bidmas. so you substitute first!

so its going to be: 3(-1)(4(-1)+5)+3

all I did is that I replaced all p's by -1 and then you multiply it!

so its gonna be: -3(-4+5)+3

you first solve what's in the brackets which is -4+5 so the answer is 1 like this: -3(1)+3 now its much simpler. all we have to do is to expand the bracket so its going to be -3+3 so the answer is 0!

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3 years ago
Can someone help please
myrzilka [38]
<h3>Answer:   15x^(7/3) - 8x^(7/4) + x + 9000</h3>

=========================================================

Explanation:

If you know the cost function C(x), to find the marginal cost, we apply the derivative.

Marginal cost = derivative of cost function

Marginal cost = C ' (x)

Since we're given the marginal cost, we'll apply the antiderivative (aka integral) to figure out what C(x) is. This reverses the process described above.

\text{Cost} = \text{antiderivative of marginal cost}\\\\\displaystyle C(x) = \int \left(35x^{4/3} - 14x^{3/4} + 1\right)dx\\\\

C(x) = \frac{1}{1+4/3}*35x^{4/3+1} - \frac{1}{1+3/4}*14x^{3/4+1} + x + D\\\\C(x) = \frac{1}{7/3}*35x^{7/3} - \frac{1}{7/4}*14x^{7/4} + x + D\\\\C(x) = \frac{3}{7}*35x^{7/3} - \frac{4}{7}*14x^{7/4} + x + D\\\\C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

D represents a fixed constant. I would have used C as the constant of integration, but it's already taken by the cost function C(x).

To determine the value of D, we plug in x = 0 and C(x) = 9000. This is because we're told the fixed costs are $9000. This means that when x = 0 units are made, you still have $9000 in costs to pay. This is the initial value. You'll find that all of this leads to D = 9000 because everything else zeros out.

Therefore, we go from this

C(x) = 15x^{7/3} - 8x^{7/4} + x + D\\\\

to this

C(x) = 15x^{7/3} - 8x^{7/4} + x + 9000\\\\

which is the final answer.

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