Question

Please help, I'm stuck​

Answer 1

Answer: Option B

$k> 0$

Step-by-step explanation:

The graph shows a radical function of the form $f(x)=a(x+k)^{\frac{1}{n}}+c$

Where n is a even number.

This type of function has its vertex at the origin when $k = 0$ and $c = 0$

If $k> 0$ the graph moves horizontally k units to the left

If $k$ the graph moves horizontally k units to the right.

Note that in this case the vertex of the function is horizontally shifted 5 units to the left. Therefore we know that $k = 5> 0$

The correct answer is option B