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storchak [24]
3 years ago
10

Michael split a rope that was 28 inches long into 5 equal parts. Brenden split a rope that was 30 inches long into 6 equal parts

. Which boy's rope was cut into longer pieces?
Mathematics
1 answer:
QveST [7]3 years ago
7 0

Answer:

  Michael

Step-by-step explanation:

The pieces of Michael's rope were (28 in)/5 = 5.6 in long.

The pieces of Brenden's rope were (30 in)/6 = 5.0 in long.

Michael's rope was cut into longer pieces.

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Write the equation of the line that is parallel to
Kruka [31]

Answer:

y = -x + 2

Step-by-step explanation:

Lines that are parallel have the same slope but different

y-intercepts.

So the slope of the parallel line is -x

We can input the x and y points given to solve for the new y-intercept

  • y = -x + b
  • 8 = -(-6) + b
  • 8 = 6 + b
  • b = 2

The new line is y = -x + 2. Since these two lines are the same, they are coinciding lines.

-Chetan K

4 0
2 years ago
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Solve the equation ​
UNO [17]

Answer:

x = 10

Step-by-step explanation:

2x/3 + 1 = 7x/15 + 3

<em><u>(times everything in the equation by 3 to get rid of the first fraction)</u></em>

2x + 3 = 21x/15 + 9

<em><u>(times everything in the equation by 15 to get rid of the second fraction)</u></em>

30x+ 45 = 21x + 135

<em><u>(subtract 21x from 30x; subtract 45 from 135)</u></em>

9x = 90

<em><u>(divide 90 by 9)</u></em>

x = 10

<h2>Another solution:</h2>

2x/3 + 1 = 7x/15 + 3

<u><em>(find the LCM of 3 and 15 = 15)</em></u>

<u><em>(multiply everything in the equation by 15, then simplify)</em></u>

10x + 15 = 7x + 45

<u><em>(subtract 7x from 10x; subtract 15 from 45)</em></u>

3x = 30

<em><u>(divide 30 by 3)</u></em>

x = 10

4 0
2 years ago
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif
algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

e) p_v =P(t_{118}  

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

\bar X_{O}=2.91 represent the mean for the Orange Coast

\bar X_{C}=2.96 represent the mean for the Coastline

s_{O}=0.05 represent the sample standard deviation for Orange Coast

s_{C}=0.03 represent the sample standard deviation for Coastline

n_{O}=60 sample size for Orange Coast

n_{C}=60 sample size for Coastline

\alpha=0.005 Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis:\mu_{O} \geq \mu_{C}  

Alternative hypothesis:\mu_{O} < \mu_{C}  

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=60+60-2=118  

Replacing the info we got:

t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

Part e

We can calculate the p value with this probability:

p_v =P(t_{118}  

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

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Answer:

82

Step-by-step explanation:

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2 years ago
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How do I graph this or how do I get a equation I can graph?​
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Answer:

y=mx+b

Step-by-step explanation:

7 0
3 years ago
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