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devlian [24]
3 years ago
14

Evaluate each expression ​

Mathematics
1 answer:
choli [55]3 years ago
6 0

Answer:

below

Step-by-step explanation:

  • c = 8 and  d = -3

c^{2} + d^{3} \\8^{2} + (-3)^{3} \\64 + (-27) \\64 - 27 \\37

  • r = -3  and   s = -4

( r -  s)^{3} + r^{2}\\(-3 -(-4))^{2} + (-3)^{2} \\(-3+4)^{3} + 9+ \\1^{3} + 9\\1 + 9 \\10

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Answer:

{x ∈ R: x<6}

Step-by-step explanation:

Given

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Required

Write the set using set builder notation

The very first thing to do is to list out the range of x, using inequalities;

x is less than 6 implies that -infiniti < x < 6

The next step is to translate this to set builder. This is done as follows

x ∈ R - > This means that x is a real number

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Bringing these two together, it gives:

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Hence, the set of real numbers x less than 6 is equivalent to {x ∈ R: x<6} using set builder notation

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3 years ago
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Lostsunrise [7]

Well,

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The quotient = x/7

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x/7 = 3x + 5 This is the answer

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