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VMariaS [17]
2 years ago
5

Jan graphed her house and the local parks on a coordinate plane. Her house is located at (-5, 6), Park A is at (4, 6), and Park

B is at (-5, -6). If each unit is 1 city block, which park is furthest from her house? How far away is it?
A) Park A is furthest at 8 blocks away.
B) Park A is furthest at 9 blocks away.
C) Park B is furthest at 11 blocks away.
D) Park B is furthest at 12 blocks away.
Mathematics
2 answers:
Ulleksa [173]2 years ago
8 0
C the park B is the furthest at 11 blocks away
N76 [4]2 years ago
7 0
C) park b is furthest at 11 blocks away
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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard
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52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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In this problem, we have that:

\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

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Z = \frac{X - \mu}{s}

Z = \frac{30054 - 30393}{472.81}

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Z = -0.72 has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

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