Ask question

Ask question

All categories

2 years ago

12

The perimeter of a triangle with two equal sides is 46 cm. If it's base were lengthened by 3 cm and each leg were shortened by 5

cm, all three sides would be equal. Find the length of the base of the original triangle

1 answer:

lana66690 [7]2 years ago

3 0

Answer:

The original triangle has sides of 18 cm, 18 cm and 10 cm

Step-by-step explanation:

Let x cm be the length of the leg of the original triangle and y cm be the length of the base of the original triangle.

1. Since the perimeter of the original triangle is 46 cm, then

x+x+y=46.

2. If it's base were lengthened by 3 cm, then it becomes y+3 cm. If each leg were shortened by 5 cm, then each leg becomes x-5 cm. All three sides became equal, then

y+3=x-5.

3. Solve the system of two equations:

$\left\{\begin{array}{l}2x+y=46\\x-5=y+3\end{array}\right.\Rightarrow \left\{\begin{array}{l}2(y+8)+y=46\\x=y+8\end{array}\right.,\ 2y+y=46-16,\ 3y=30,\ y=10\ cm.$

Then $x=10+8=18\ cm.$

You might be interested in

The green triangle is a dilation of the red triangle with a scale factor of s=1/3 and the center of dilation is at the point (4,

klasskru [66]

Given:

The scale factor is $s=\dfrac{1}{3}$ and the center of dilation is at the point (4,2).

Red is original figure and green is dilated figure.

To find:

The coordinates of point C' and point A.

Solution:

Rule of dilation: If a figure is dilated with a scale factor k and the center of dilation is at the point (a,b), then

$(x,y)\to (k(x-a)+a,k(y-b)+b)$

According to the given information, the scale factor is $\dfrac{1}{3}$ and the center of dilation is at (4,2).

$(x,y)\to (\dfrac{1}{3}(x-4)+4,\dfrac{1}{3}(y-2)+2)$ ...(i)

Let us assume the vertices of red triangle are A(m,n), B(10,14) and C(-2,11).

Using (i), we get

$C(-2,11)\to C'(\dfrac{1}{3}(-2-4)+4,\dfrac{1}{3}(11-2)+2)$

$C(-2,11)\to C'(\dfrac{1}{3}(-6)+4,\dfrac{1}{3}(9)+2)$

$C(-2,11)\to C'(-2+4,3+2)$

$C(-2,11)\to C'(2,5)$

Therefore, the coordinates of Point C' are C'(2,5).

We assumed that point A is A(m,n).

Using (i), we get

$A(m,n)\to A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)$

From the given figure it is clear that the image of point A is (8,4).

$A'(\dfrac{1}{3}(m-4)+4,\dfrac{1}{3}(n-2)+2)=A'(8,4)$

On comparing both sides, we get

$\dfrac{1}{3}(m-4)+4=8$

$\dfrac{1}{3}(m-4)=8-4$

$(m-4)=3(4)$

$m=12+4$

$m=16$

And,

$\dfrac{1}{3}(n-2)+2=4$

$\dfrac{1}{3}(n-2)=4-2$

$(n-2)=3(2)$

$n=6+2$

$n=8$

Therefore, the coordinates of point A are (16,8).

5 0

2 years ago

G= 2/3ns <br><br>solve for variable "s"

Kisachek [45]

“S” = 3g /2n
I would think

6 0

2 years ago

PLEASE HELP ME ANSWER THIS QUESTION! QUICK POINTS!!!

Svetllana [295]

Step-by-step explanation:

2.5<x<8.0???????????

3 0

2 years ago

Read 2 more answers

he coordinate grid shows the graph of four equations: A coordinate grid is shown from negative 12 to positive 12 on the x axis a

denis23 [38]

The set of equation that is known to have 5 and 0 as solutions is A and B.

<h3>How to solve for the system of equations.</h3>

From the graph that we have here in this question, we are supposed to identify the equations that have this point.

We can do this by tracing the lines in order to locate 5 and 0 on the grid.

When we trace the bine that has 5 and 0, We would find out that it is traceable to A and B.

Read more on graphs here:

brainly.com/question/10465970

#SPJ1

6 0

2 years ago

A tree initially measured 3812 feet tall. Over the next 512 years, it grew to a final height of 4912 feet. During those 512 year

Arlecino [84]

Answer:

2 feet per year

Step-by-step explanation:

I think you meant 38 1/2

and 5 1/2

but if you didn't then its

2.1484375

because

4912-3812=1100

1100÷512= 2.1484375

3 0

2 years ago