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Nastasia [14]
3 years ago
12

How do you write the slope and the y-intercept of the line​

Mathematics
1 answer:
Readme [11.4K]3 years ago
4 0

Answer:

The equation is y=mx+b, where m= slope and b= y-intercept

If your slope was 2 and your intercept was 3, it would look like:

y= 2x+3

Step-by-step explanation:

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Step 1:
Set Variables (We will use x & y)

x = years
y = total orangutan population

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A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,
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We have been given that a huge ice glacier in the Himalayas initially covered an area of 45 square kilo-meters. The relationship between A, the area of the glacier in square kilo-meters, and t, the number of years the glacier has been melting, is modeled by the equation A=45e^{-0.05t}.

To find the time it will take for the area of the glacier to decrease to 15 square kilo-meters, we will equate A=15 and solve for t as:

15=45e^{-0.05t}

\frac{15}{45}=\frac{45e^{-0.05t}}{45}

\frac{1}{3}=e^{-0.05t}

Now we will switch sides:

e^{-0.05t}=\frac{1}{3}

Let us take natural log on both sides of equation.

\text{ln}(e^{-0.05t})=\text{ln}(\frac{1}{3})

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

-0.05t\cdot \text{ln}(e)=\text{ln}(\frac{1}{3})

-0.05t\cdot (1)=\text{ln}(\frac{1}{3})

-0.05t=\text{ln}(\frac{1}{3})

t=\frac{\text{ln}(\frac{1}{3})}{-0.05}

t=\frac{\text{ln}(\frac{1}{3})\cdot 100}{-0.05\cdot 100}

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Therefore, it will take 20\text{ln}(3) years for area of the glacier to decrease to 15 square kilo-meters.

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