I put in the x coordinate for where y was 80 and the y coordinate for where x was 3. Then I subtracted them to get the slope. Hope this helps.
If cos theta =-2/3, which of the following are possible
1 answer:
Well, the cos(∅) is negative in the second and third quadrants. If you are solving for theta, you would use the inverse of the cos or arccos
take the inverse of both sides to get:
x = arccos(-2/3) now evaluate the right
x = 131.8103149 degrees
to find your second solution, subtract your reference angle from 360 degrees.
360 - 131.8103149 = 228.1896851 degrees
Now the period of cos is 2π or 360 degrees. So if you want to consider all possible solutions, you would need to add/subtract 360n to both solutions above..
Not sure if this is what you're looking for, but thought I would leave it here for you just in case... As a side note, you could do this problem in radian measurement as well.
x = arccos(-2/3) now evaluate the right
x = 131.8103149 degrees
to find your second solution, subtract your reference angle from 360 degrees.
360 - 131.8103149 = 228.1896851 degrees
Now the period of cos is 2π or 360 degrees. So if you want to consider all possible solutions, you would need to add/subtract 360n to both solutions above..
Not sure if this is what you're looking for, but thought I would leave it here for you just in case... As a side note, you could do this problem in radian measurement as well.
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Answer:
Perimeter units. Area 12 square units.
Step-by-step explanation:
Perimeter: total distance around the figure.
Distance Formula: the distance between points is
The perimeter is the sum of all those segment lengths.
One way to find the area of the figure is to surround it with a rectangle, insert some lines so that the areas you do not want can be found and subtracted from the rectangle's area. (See attached image.)
The area of the large rectangle around the figure is 5 x 4 = 20 square units.
The triangles have areas 1/2 (base) (height):
A. (1/2)(1)(4) = 2 square units
B. (1/2)(3)(1) = 1.5 square units
D. (1/2)(1)(2) = 1 square unit
E. (1/2)(5)(1) = 2.5 square units
Square C. (1)(1) = 1 square unit
Total of all the area you don't want to include:
2 + 1.5 + 1 + 2.5 + 1 = 8 square units
Subtract 8 from the surrounding rectangle's area of 20, and you get the area of the figure is 20 - 8 = 12 square units.
