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3 years ago

-2.2 + 0.3z= 3 -0.5z -0.8z what does z equal

Mathematics

2 answers:

dsp733 years ago

8 0

-2.2+0.3z = 3-0.5z-0.8z

-2.2 = 3-0.5z-0.8z-0.3z

-5.2 = -1.6z

z = -5.2 / -1.6

z = -3.25

wariber [46]3 years ago

3 0

$-2.2 + 0.3z= 3 -0.5z -0.8z \\ \\ 0.3z - 2.2 = 3 - 0.5z - 0.8z \\ \\ 0.3z - 2.2 = 3 - 1.3z \\ \\ 0.3z = 3 - 1.3z + 2.2 \\ \\ 0.3z = -1.3z + 5.2 \\ \\ 0.3z + 1.3z = 5.2 \\ \\ 1.6z = 5.2 \\ \\ z = 3.25 \\ \\$

The final result is: z = 3.25.

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A ball is thrown vertically in the air with a velocity of 95 ft/s. The ball is at a height of 120 ft.

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Answer:

The ball is at a height of 120 feet after 1.8 and 4.1 seconds.

Step-by-step explanation:

The statement is incomplete. The complete statement is perhaps the following "A ball is thrown vertically in the air with a velocity of 95 ft/s. What time in seconds is the ball at a height of 120ft. Round to the nearest tenth of a second."

Since the ball is launched upwards, gravity decelerates it up to rest and moves downwards. The position of the ball can be determined as a function of time by using this expression:

$y = y_{o} + v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}$

Where:

$y_{o}$ - Initial height of the ball, measured in feet.

$v_{o}$ - Initial speed of the ball, measured in feet per second.

$g$ - Gravitational constant, equal to $-32.174\,\frac{ft}{s^{2}}$ .

$t$ - Time, measured in seconds.

Given that $y_{o} = 0\,ft$ , $v_{o} = 95\,\frac{ft}{s}$ , $g = -32.174\,\frac{ft}{s^{2}}$ and $y = 120\,ft$ , the following second-order polynomial is found:

$120\,ft = 0\,ft + \left(95\,\frac{ft}{s} \right)\cdot t +\frac{1}{2}\cdot \left(-32.174\,\frac{ft}{s^{2}} \right) \cdot t^{2}$

$-16.087\cdot t^{2} + 95\cdot t -120 =0$

The roots of this polynomial are, respectively:

$t_{1} \approx 4.075\,s$ and $t_{2} \approx 1.831\,s$ .

Both roots solutions are physically reasonable, since $t_{1}$ represents the instant when the ball reaches a height of 120 ft before reaching maximum height, whereas $t_{2}$ represents the instant when the ball the same height after reaching maximum height.

In nutshell, the ball is at a height of 120 feet after 1.8 and 4.1 seconds.

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Step-by-step explanation:

Given,

The length of the edge of the cube (a) = 5 cm

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