The show has a large display board where visitors are encouraged to pin up their own instant camera pictures, taken during the e
vent. The board is shown below.
How many 6 cm by 6 cm pictures could fit on the wall?
How many 6 cm by 6 cm pictures could fit on the wall?
1 answer:
Answer:
<h2>1,800 pictures</h2>Step-by-step explanation:
Find the diagram attached below with its dimension.
The board is rectangular in nature with dimension of 3.6 m by 1.8 m wall.
Area of a rectangle = Length * Breadth
Area of the board = 3.6 m * 1.8 m
since 1m -= 100cm
Area of the board = 360cm * 180cm
Area of the board = 64,800cm²
If the dimension of a picture on the wall is 6cm * 6cm, the area of one picture fir on the wall = 6cm* 6cm = 36cm²
In order to know the amount of 6cm* 6cm pictures that will fit on the wall, we will divide the area of the board by the area of one picture as shown;
Number of 6cm by 6cm pictures that could fit on the wall
= 64, 800cm²/36cm²
= 1,800 pictures
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(You go from left to right)
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
^Hope this helps.
For this case we have the following functions:
When composing the functions we have:
Substituting values we have:
Rewriting:
The function has a horizontal asymptote at y = 3.
Therefore, the range of the function is all reals minus y = 3.
Answer:
option 3
Substituting values we have:
Rewriting:
The function has a horizontal asymptote at y = 3.
Therefore, the range of the function is all reals minus y = 3.
Answer:
option 3