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3 years ago

Please help, will mark brainliest, do not do for points or I will report, explanation please or no brainliest

Mathematics

2 answers:

Molodets [167]3 years ago

7 0

ANSWER:

(2y - 1)(2y + 1)

Using identity (a + b)(a - b) = a² - b².

(2y)² - (1)²

4y² - 1.

sladkih [1.3K]3 years ago

4 0

Answer:

to multiply-----

(2y-1)(2y+1)

2y(2y+1)-1(2y+1)

4y^2+2y-2y-1

=4y^2-1

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Part A)

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2) $y=25$

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1) $k=7$

2) $y=84$

Step-by-step explanation:

Part 1) x and y vary inversely and x=50 when y=5 find y when x=10 what is k?

we know that

A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form $y*x=k$ or $y=k/x$

step 1

Find the value of k

x=50 when y=5

substitute the values

$y*x=k$ ------> $5*50=k$ -----> $k=250$

The equation is equal to

$y*x=250$ or $y=250/x$

step 2

Find y when x=10

substitute the value of x in the equation and solve for y

$y*(10)=250$

$y=250/10=25$

Part B) x and y vary directly and x=6 when y=42 find k what is y when x=12

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

step 1

Find the value of k

x=6 when y=42

substitute the values

$y/x=k$ ------> $42/6=k$ -----> $k=7$

The equation is equal to

$y/x=7$ or $y=7x$

step 2

Find y when x=12

substitute the value of x in the equation and solve for y

$y=7(12)=84$

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3 years ago