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joja [24]
3 years ago
9

Find the unknown measures. Round lengths to the nearest tenth and angle measures to the nearest degree.

Mathematics
1 answer:
ioda3 years ago
3 0

Answer:

AC= 6.3 units (nearest tenth)

BC= 2.8 units (nearest tenth)

∠C= 64°

Step-by-step explanation:

Please see attached picture for full solution.

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Stephanie wants to buy s tomato plants.
max2010maxim [7]

Answer:

Required Expression : 7·(s + d) - 25

Step-by-step explanation :

Cost of each plant both buys = $7

No. of plants Stephanie wants to buy = s

Total cost of plants bought by Stephanie = 7·s

No. of plants Diego wants to buy = d

Total cost of plants bought by Diego = 7·d

Total cost = 7·s + 7·d

                 = 7·(s + d)

Discount applied through coupon = $25

So, Total cost of all their plants with discount = 7·(s + d) - 25

4 0
3 years ago
7. Solve for b.<br> b<br> 26°
Genrish500 [490]

Answer:

64°

Step-by-step explanation:

We know that a right angle is 90°

so we do 90° - 26° = 64°

6 0
2 years ago
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A circle is centered at J(3, 3) and has a radius of 12.
stealth61 [152]

Answer:

(-6,\, -5) is outside the circle of radius of 12 centered at (3,\, 3).

Step-by-step explanation:

Let J and r denote the center and the radius of this circle, respectively. Let F be a point in the plane.

Let d(J,\, F) denote the Euclidean distance between point J and point F.

In other words, if J is at (x_j,\, y_j) while F is at (x_f,\, y_f), then \displaystyle d(J,\, F) = \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}.

Point F would be inside this circle if d(J,\, F) < r. (In other words, the distance between F\! and the center of this circle is smaller than the radius of this circle.)

Point F would be on this circle if d(J,\, F) = r. (In other words, the distance between F\! and the center of this circle is exactly equal to the radius of this circle.)

Point F would be outside this circle if d(J,\, F) > r. (In other words, the distance between F\! and the center of this circle exceeds the radius of this circle.)

Calculate the actual distance between J and F:

\begin{aligned}d(J,\, F) &= \sqrt{(x_j - x_f)^{2} + (y_j - y_f)^{2}}\\ &= \sqrt{(3 - (-6))^{2} + (3 - (-5))^{2}} \\ &= \sqrt{145}  \end{aligned}.

On the other hand, notice that the radius of this circle, r = 12 = \sqrt{144}, is smaller than d(J,\, F). Therefore, point F would be outside this circle.

5 0
3 years ago
Explain one strAtegy for finding 2 2/5 + 1 2/5.
Monica [59]

Answer:

3 4/5

Step-by-step explanation:

just add the whole number then add the numerator then the denominator stay the same

4 0
3 years ago
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HELP ASAP. GIVING 20P AND BRAINLIEST
PilotLPTM [1.2K]

Answer:

B

Step-by-step explanation:

edge 2020

3 0
3 years ago
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