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3 years ago

Find the line’s slope and a point line (HELP PLEASE)

Mathematics

1 answer:

algol [13]3 years ago

3 0

Slope: 1/4

A point on the line: (0, 17/4)

I rewrote the equation in slope intercept form (y=mx+b), it was y=1/4x+17/4

The slope is m, and b is the y intercept (where the line crosses the y - axis), that's the easiest point to find if you have the equation.

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4) A garden is in the shape of a square with a perimeter of

Leni [432]

Answer:

It costs $154.88 to build the fences.

Step-by-step explanation:

Perimeter of square = $4 \times Side$

We are given that A garden is in the shape of a square with a perimeter of 56 feet.

So, $4 \times side = 56$

Side = $\frac{56}{4}=14 feet$

So, Side of square park = 14 feet

One fence is around the perimeter of the garden, whereas the second fence is 2 feet from the first fence on the outside.

Outer length = 14+2+2=18 feet

So, Perimeter of outer fence = $4 \times side = 4 \times 18 = 72 feet$

Cost of fencing 1 foot = $1.21

Cost of fencing 56 feet = $56 \times 1.21=67.76$

Cost of fencing 72 feet = $72 \times 1.21=87.12$

Total cost = 67.76+87.12=154.88

Hence It costs $154.88 to build the fences.

7 0

3 years ago

With individual lines at the checkouts, a store manager finds that the standard deviation for the waiting times on Monday mornin

Arturiano [62]

Answer:

0.9

Step-by-step explanation:

6 0

3 years ago

How to know if true or false?? HELP ASAP thank you! <br><br> picture added.

Tom [10]

True
Because a negative square root is an i

7 0

3 years ago

Which of the following shapes is the cross-section for a cylinder?

Step2247 [10]

The cross-section of a cylinder is in the shape of a Circle

5 0

3 years ago

PLEASE HELP IT IS VERY URGENT!!

gogolik [260]

Step-by-step explanation:

(c)

$In\: \triangle PLM \: \&\: \triangle PLM\\\angle PLM \cong\triangle PFG.. (corresponding \:\angle s) \\\angle LPM \cong \angle FPG.. (common \: \angle s) \\\therefore \triangle PLM\sim\triangle PFG.. (by\: AA\:Postulate) \\PF = PL + LF = 2 + 3 = 5$

By area of similar triangle theorem:

$\frac {A(\triangle PLM)}{A(\triangle PFG)}= \frac{PL^2}{PF^2}\\\therefore \frac {A(\triangle PLM)}{A(\triangle PFG)}= \frac{2^2}{5^2}\\\therefore \frac {A(\triangle PLM)}{A(\triangle PFG)}= \frac{4}{25}\\A(\triangle PLM)\: :\: A(\triangle PFG) = 4 \: :\: 25$

8 0

3 years ago