Answer:
20 units²
Step-by-step explanation:
The x-intercepts are symmetrically located around the x-coordinate of the vertex, so are at
1.5 ± 5/2 = {-1, 4}
Using one of these we can find the unknown parameter "a" in the parabola's equation (in vertex form) ...
0 = a(4 -1.5)² +12.5
0 = 6.25a +12.5 . . . . . simplify
0 = a +2 . . . . . . . . . . . divide by 6.25
-2 = a
Then the standard-form equation of the parabola is ...
y = -2(x -1.5)² +12.5 = -2(x² -3x +2.25) +12.5
y = -2x² +6x +8
This tells us the y-intercept is 8. Then the relevant triangle has a base of 5 units and a height of 8. Its area is given by the formula ...
A = (1/2)bh = (1/2)(5)(8) = 20 . . . . units²
Answer:
it’s +
and it equals 46/45
Step-by-step explanation:
Answer:
n = 8
Step-by-step explanation:
Complementary angles add up to 90°
So,
59° + (4n - 1) = 90°
4n - 1 = 90° - 59° = 31°
4n = 31° + 1° = 32°
4n° = 32°
n = 32 ÷ 4 = 8
We can use the equation:
f = 3.25s
3.25 is the cups of flour used for every cup of sugar.
Where 'f' represents flour and 's' represents sugar.
The fourth or the D) Option is correct.
To find the new induced matrix via a scalar quantified multiplication we have to multiply the scalar quantity with each element surrounded and provided in a composed (In this case) 3×3 or three times three matrix comprising 3 columns and 3 rows for each element which is having a valued numerical in each and every position.
Multiply the scalar quantity with each element with respect to its row and column positioning that is,
Row × Column. So;
(1 × 1) × 7, (2 × 1) × 7, (3 × 1) × 7, (1 × 2) × 7, (2 × 2) × 7, (3 × 2) × 7, (1 × 3) × 7, (2 × 3) × 7 and (3 × 3) × 7. This will provide the final answer, that is, the D) Option.
To interpret and make it more interesting in LaTeX form. Here is the solution with LaTeX induced matrix.
Hope it helps.
