Answer: -1/2, -0.22, 0, 12%, 0.56
Step-by-step explanation:
-1/2 is equal to -0.50, making it the number with the least value.
-0.22 is closer to 0 than -0.50, meaning it is greater then -0.50 and less than 0.
0 is between the negative and positive numbers, giving it the spot that it has.
12% is equivalent to 0.12, meaning it is more than 0, and less than 0.56, which is the greatest number.
0.56 has more value than any other number in the problem, meaning it goes last in the order.
Hi there!
Let the first number be represented by X.
The second number (which is 2 more than four times the other), can be represented by 4X + 2.
We can now find the sum of this expression.
X + 4X + 2
Collect terms
5X + 2
The sum of the numbers is 18. Therefore we can set up the following equation.
5X + 2 = 18
Subtract 2.
5X = 16
Divide both sides by 5.
X = 16/5 = 3 1/5.
Therefore, the first number is 3 1/5. To find the second number we must plug in X = 3 1/5 into the expression 4X + 2
4 * (3 1/5) + 2 = 12 4/5 + 2 = 14 4/5
The two numbers are

~ Hope this helps you!
Answer:
The equation for nth term is 3n + 5.
Step-by-step explanation:
Let a1 be a,
a3 = a + (n - 1)d
or, 14 = a + (3 - 1)d
so, 14 = a + 2d
Now,
a5 = a + (n - 1)d
or, 20 = a + (5 - 1)d
or, 20 = a + 4d
now,
a + 4d = 20
a + 2d = 14
now,
a + 4d - ( a + 2d) = 20 - 14
or, a + 4d - a - 2d = 6
or, 2d = 6
so, d = 3
Now,
a + 2d = 14
or, a + 2(3) = 14
or, a = 14 - 6
so, a = 8
Now,
an = a + (n - 1)d
or, an = 8 + (n - 1)3
or, an = 8 + 3n - 3
so, an = 3n + 5
The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.
Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:
(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)
This is the vector equation; getting the parametric form is just a matter of delineating
<em>x</em>(<em>t</em>) = 1 + <em>t</em>
<em>y</em>(<em>t</em>) = 3<em>t</em>
<em>z</em>(<em>t</em>) = 6 + <em>t</em>