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2 years ago

Mark bought 4 pounds of apples for 7.56 what was the cost per pound

Mathematics

2 answers:

Hunter-Best [27]2 years ago

6 0

Answer:

1.89 per pound

Step-by-step explanation:

7.56/4=1.89

marusya05 [52]2 years ago

3 0

Answer:

1.89

Step-by-step explanation:

7.56 ÷ 4 = 1.89

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What does r stand for in the formula 2.rr.?

klemol [59]

Answer:

r = radius of circle

Step-by-step explanation:

The circumference of a circle is given by :

C = 2πr

Where

r is the radius of the circle

In this problem, we need to say that what does r represents in the given formula. It means we can say that r stands for the radius of the circle.

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2 years ago

A survey all beings on plant Kent found that 20 beings preferred Freon juice to all other juices. If 50 beings surveyed altogeth

Ugo [173]

Answer: 40%

Step-by-step explanation:

Since 20 beings preferred Freon juice to all other juices and there were 50 people that were surveyed, the percentage of those that preferred Freon Juice will be:

= Those that preferred Freon Juice / Total number surveyed. × 10

= 20/50 × 100

= 40%

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2 years ago

What should she do next?

s2008m [1.1K]

Answer:

(-2) *6 = -12

Step-by-step explanation:

4 + (2-4) *6 , solve the subtraction in parenthesis

4 + (-2)*6, solve the multiplication of (-2) *6

4 - 12, solve the subtraction

-8

8 0

2 years ago

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

How to find HCF of 16 24 and 36 by long division method

oee [108]

Answer:

GCF=4

Step-by-step explanation:

16/4=4

24/4=6

36/4=9

7 0

2 years ago