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slava [35]
3 years ago
9

Find the slope of the line passing through the pair of points: (-6,-1), (-6,4)

Mathematics
1 answer:
Dima020 [189]3 years ago
8 0

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (-6, -1) and (-6, 4).

Substitute:

m=\dfrac{4-(-1)}{-6-(-6)}=\dfrac{4+1}{-6+6}=\dfrac{5}{6}\ !!!

Dividing by 0 is not possible, therefore the slope is undefined.

<em>It's a vertical line x = -6</em>.

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Lauren Rob need to find a decimal equivalent to 39/50 Laura said she could write an equivalent fraction with 100 as the denomina
Lina20 [59]

Answer:

Laura and Rob are correct

Step-by-step explanation:

we have

39/50

1) Rob said he could divide the numerator by the denominator

so

using a calculator

39/50=0.78

Rob is correct

2) Laura said she could write an equivalent fraction with 100 as the denominator to converted into a decimal

so

Multiply by 2/2

(39/50)*(2/2)=78/100=0.78

Laura is correct

therefore

Laura and Rob are correct

5 0
3 years ago
How to do this because I don't know my class work
salantis [7]
I assume the answer is 1/4
5 0
4 years ago
How do i find the slant asymptope of x^3/(2(x+2)(x-4) aka x^3/(2x^2-8)
hram777 [196]
I’m really sorry I just don’t know I guess I’m. It smart enough try to look it up and wait for someone else to answer sorry again :(
6 0
3 years ago
What is the answer to X(x+7)
LekaFEV [45]

Answer:

\boxed{ \bold{ \boxed {\huge{ \sf{ {x}^{2}  + 7x}}}}}

Step-by-step explanation:

\sf{x(x + 7)}

Distribute x through the parentheses

\dashrightarrow{ \sf{x \times x + x \times 7}}

\dashrightarrow{ \boxed{ \sf{ {x}^{2}  + 7x}}}

Hope I helped!

Best regards! :D

3 0
3 years ago
An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (An ordinary (fair) coin is tossed 3 times. Ou)
shepuryov [24]

Answer:

Probability distribution

X    P(X)

0    1/8

1     3/8  

2    3/8

3     1/8

Step-by-step explanation:

When a coin is tossed there are two outcomes head and tail. When three coins are tossed the possible outcomes are

Sample space=S={HTH,THH,TTH,HHH,HTT,THT,TTT,HHT}

The total number of outcomes is n(S)=8. The X be the random variable counting number of tails in each outcome and so X can take values as 0,1,2,3. The probabilities can be computed as P(X)=n(X)/n(S). The probabilities are calculated as under:

X   Outcomes           P(X)

0    HHH                    1/8

1     HHT,THH,HTH    3/8  

2    TTH,HTT,THT     3/8

3    TTT                        1/8

The probability distribution of X is as under:

X    P(X)

0    1/8

1     3/8  

2    3/8

3     1/8

4 0
4 years ago
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