Hi someone pls help me it’s rly important
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Answer:
decreasing at 11.99 ft/s
Step-by-step explanation:
The path from 1st base to 2nd base and that from 2nd base to 3rd base form the legs of a right triangle. The hypotenuse of that triangle is the distance between the runners.
If the distance between bases is 90 ft (as in major-league baseball), then the runner on first has distance from second of ...
... 90 -18t . . . . . . . where t is the time in seconds since he left 1st base
The runner on second has a distance from second of
... 20t . . . . . . . . . . where t is the time in seconds since he left 2nd base
Then the Pythagorean theorem tells us the distance between the runners is
... d = √((90 -18t)² +(20t)²)
The rate of change of distance between the runners is the derivative of this with respect to time.
The distance between runners is decreasing at 11.99 ft/s one second after they leave the bases.
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<em>Comment on the solution</em>
If you look carefully at the derivative expression, you find it is the sum of each of the speeds multiplied by the cosine of the angle between the direction of running and the direction of the other runner. As we found above, the distance between runners is √5584 ≈ 74.7262 ft, so the runner from first base is decreasing the distance at the rate of ...
... (18 ft/s)×(72 ft)/(74.7262 ft) ≈ 17.3433 ft/s
At the same time, the runner from second base is increasing the distance between them at ...
... (20 ft/s)×(20 ft)/(74.7262 ft) ≈ 5.3529 ft/s
So, the distance between runners is changing at the rate of
... -17.3433 +5.3529 = -11.9904 . . . . ft/s
No derivatives are necessary in this approach to the solution.