1 answer:
We presume you want to find values of x that make this true.
Subtract the right side and factor:
Once you have factors whose product is zero, you can find the values of x that make those factors zero. A product can only be zero if one or more contributing factors is zero.
To solve 2x-5=0, you can add 5 then divide by 2:
... 2x -5 = 0
... 2x = 5
... x = 5/2
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well, we can say that 1 hour is 100%, what is 2/5 hr off of it in percentage?
Answer:
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum weight for a passenger who outweighs at least 90% of the other passengers?
90th percentile
The 90th percentile is X when Z has a pvalue of 0.9. So it is X when Z = 1.28. So
The minimum weight for a passenger who outweighs at least 90% of the other passengers is 203.16 pounds