Question

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Answer 1

We presume you want to find values of x that make this true.

Subtract the right side and factor:

$2x^2-5x=0\\\\x(2x-5)=0\\\\\bf{x=0\qquad\text{or}\qquad x=\dfrac{5}{2}}$

Once you have factors whose product is zero, you can find the values of x that make those factors zero. A product can only be zero if one or more contributing factors is zero.

To solve 2x-5=0, you can add 5 then divide by 2:

... 2x -5 = 0

... 2x = 5

... x = 5/2