<img src="https://tex.z-dn.net/?f=2%7Bx%7D%5E%7B2%7D%20%20%3D%205x" id="TexFormula1" title="2{x}^{2} = 5x" alt="2{x}^{2} = 5x"

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morpeh [17]

3 years ago

align="absmiddle" class="latex-formula">

Mathematics

1 answer:

lilavasa [31]3 years ago

4 0

We presume you want to find values of x that make this true.

Subtract the right side and factor:

$2x^2-5x=0\\\\x(2x-5)=0\\\\\bf{x=0\qquad\text{or}\qquad x=\dfrac{5}{2}}$

Once you have factors whose product is zero, you can find the values of x that make those factors zero. A product can only be zero if one or more contributing factors is zero.

To solve 2x-5=0, you can add 5 then divide by 2:

... 2x -5 = 0

... 2x = 5

... x = 5/2

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