Question

In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, what is the probability you will choose a consonant and then a vowel?

Answer 1

Answer: 0.21

Step-by-step explanation:

Given: The number of vowels in the bag = 28

The number of consonants= 12

The total number of letters in the bag = $28+12=40$

Probability of choosing consonant :-

$P(C)=\dfrac{12}{40}=\dfrac{3}{10}$

After replacement the total number of letters remains same.

Probability of choosing vowel :-

$P(V)=\dfrac{28}{40}=\dfrac{7}{10}$

Now, the  probability you will choose a consonant and then a vowel (independent events) is given by :-

$P(C)\times P(V)=\dfrac{3}{10}\times\dfrac{7}{10}=\dfrac{21}{100}=0.21$