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Nonamiya [84]
3 years ago
14

In a word game, you choose a tile from a bag, replace it, and then choose another. If there are 28 vowels and 12 consonants, wha

t is the probability you will choose a consonant and then a vowel?
Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

Answer: 0.21

Step-by-step explanation:

Given: The number of vowels in the bag = 28

The number of consonants= 12

The total number of letters in the bag = 28+12=40

Probability of choosing consonant :-

P(C)=\dfrac{12}{40}=\dfrac{3}{10}

After replacement the total number of letters remains same.

Probability of choosing vowel :-

P(V)=\dfrac{28}{40}=\dfrac{7}{10}

Now, the  probability you will choose a consonant and then a vowel (independent events) is given by :-

P(C)\times P(V)=\dfrac{3}{10}\times\dfrac{7}{10}=\dfrac{21}{100}=0.21

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