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kvv77 [185]
3 years ago
15

Which of these is a subdirectory? HTTPS /FAQ .org WWW

Computers and Technology
1 answer:
Katyanochek1 [597]3 years ago
8 0

Answer:

/FAQ

Explanation:

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IF YOU COULD CREATE A SOCIAL NETWORK:, what would it be like? What would make it so special about the others? (If you want you c
frosja888 [35]

It would be like instagram

3 0
3 years ago
write a simple assembly code using 8088 microprocessor instruction set to add two numbers ? please help me if you know :(​
Kay [80]

Answer:

sexxxxx chaaaaat insta id abhilash0351

3 0
3 years ago
Write a function that takes as input a single integer parameter n and computes the nth Fibonacci Sequence number. The Fibonacci
RSB [31]

Answer:

Following are the code to this question:

def Fibonacci(n):#defining a method Fibonacci that accept a parameter

   a = 1#defining a variable a that holds a value 1

   b = 1#defining a variable b that holds a value 1

   if n <= 0:# Use if to check n value

       print("invalid number")#print message

   elif n == 2:#defining elif that check n equal to 2

        return 1#return 1

   else:#defining else block

       print(a)#print value of a

       print(b)#print value of b

       for i in range(2,n):#defining for loop to calculate series

           s = a + b# add value in s variable

           a = b # interchange value

           b = s# hold s value

           print(s)#print s value

Fibonacci(10)#calling method

Output:

1

1

2

3

5

8

13

21

34

55

Explanation:

In the above-given program code, a method "Fibonacci" is defined, which holds a value "n" in its parameter, and inside the method two-variable "a and b" is defined, that holds a value "1".

  • In the next step, if a block is defined that checks n value is less than equal to 0, it will print "invalid number" as a message.
  • In the elif, it checks n value is equal to 2 it will return a value that is 1.
  • In the else block, it will calculate the Fibonacci series and print its value.
4 0
2 years ago
for java ?(Business: check ISBN-13)ISBN-13 is a new standard for identifying books. It uses 13 digits d1d2d3d4d5d6d7d8d9d10d11d1
ludmilkaskok [199]

Answer:

In Java:

import java.util.*;

public class Main{

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 String isbn;

 System.out.print("First 1:2 digits: ");

 isbn = input.nextLine();

 if(isbn.length()==12){

 int chksum = 0;

 for(int i = 0; i<12;i++){

     if((i+1)%2==0){      chksum+= 3 * Character.getNumericValue(isbn.charAt(i));          }

     else{          chksum+=Character.getNumericValue(isbn.charAt(i));          }  }

 chksum%=10;

 chksum=10-chksum;

 if(chksum==10){

 System.out.print("The ISBN-13 number is "+isbn+"0");}

 else{

 System.out.print("The ISBN-13 number is "+isbn+""+chksum);          }   }

 else{

     System.out.print("Invalid Input");

 }     }}

Explanation:

See attachment for explanation where comments are used to explain each line

Download txt
6 0
3 years ago
Does anyone know the code for the beaded bracelet on codehs? pls i really need help
kvv77 [185]

Answer:

Explanation:

If it has not changed since the last time that i used codehs then the code should be the following

penup()

forward(-100)

right(90)

pendown()

def beaded_bracelet():

circle(10)

penup()

forward(20)

left(10)

pendown()

for i in range(36):

beaded_bracelet()

Which should complete the entire function as intended.

6 0
2 years ago
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