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riadik2000 [5.3K]
3 years ago
13

Write 6.8 ad mixed number?

Mathematics
2 answers:
k0ka [10]3 years ago
6 0
8/10 but if u simplify it its 0.8
aleksley [76]3 years ago
6 0
6 4/5 is 6.8 as a mixed fraction.
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In AOPQ, mZO = (6x – 14)°, mZP = (2x + 16)°, and mZQ = (2x + 8)°. Find mZQ.
loris [4]
\measuredangle Q=42

Explanation

Step 1

the sum of the internal angles in a triangle equals 18o, so

\begin{gathered} (2x+16)+(6x-14)+(2x+8)=180 \\ 2x+16+6x-14+2x+8=180 \\ \text{add similar terms} \\ 10x+10=180 \\ \text{subtract 10 in both sides} \\ 10x+10-10=180-10 \\ 10x=170 \\ \text{divide both sides by 10} \\ \frac{10x}{10}=\frac{170}{10} \\ x=17 \end{gathered}

Step 2

now, replace the value of x in angle Q to find it

\begin{gathered} \measuredangle Q=(2x+8) \\ \measuredangle Q=(2\cdot17+8) \\ \measuredangle Q=(34+8) \\ \measuredangle Q=42 \end{gathered}

I hope this helps you

8 0
1 year ago
Please i need workings for these questions. Any kind of help will be appreciated.
Anna11 [10]

Answer:

1. N4 = a

2. N8.25 = b

Step-by-step explanation:

1000 litre =N3

Each additional 100 litres = 5 k

100 litres

2000 litres

100 litres =5k

2000 litres = x

100x =5×2000

100x =10,000

Divide both sides of the equation by 100

x = 100k

100 Kobo = N1

x =N1

N3+N1 =N4

2. First ten words cost N6

Each additional word cost 45 k

1= 45k

5=x

x = 5×45

= 225 Kobo

100 Kobo = 1 Naira

225 Kobo = x

x = N2.25

N6 + N2.25

x = N8.25 = B

4 0
3 years ago
The first equation from the previous system of
VladimirAG [237]

Answer: (3, -2)

Step-by-step explanation:

The solution to the system is where the graphs intersect.

3 0
2 years ago
X + 4y = -3 x + 7y = - 12 *
Leokris [45]

Answer:

??? Please be specific

Step-by-step explanation:

5 0
4 years ago
As part of his retirement strategy, John plans to invest $210,000 in two different funds. He projects that the moderately high r
Maslowich

Answer:

Therefore he invested $60,000 at 9% per year and $(210,000-60,000)=$150,000 at 4% per year.

Step-by-step explanation:

Given John plans to invest $210,000 in two different funds. He projects that the moderately high risk investments should return, overtime 9% per year,while low risk investments should return about 4% per year.

He wants a supplemental income of$11,400 a year.

Let , he invested $x at 9% per year and $(210,000-x) at 4% per year.

interest=\frac{prt}{100}   p = principle , r = rate of interest and t = time

The interest earns at 9% per year= \frac{x\times 9\times 1}{100}

The interest earns at 4% per year=\frac{(210,00-x)\times 4 \times 1}{100}

According to the problem,

\frac{x\times 9\times 1}{100}+\frac{(210,00-x)\times 4 \times 1}{100}= 11400

\Leftrightarrow 9x+840000-4x=11400 \times 100

\Leftrightarrow 5x=1140000-840000

\Leftrightarrow x=\frac{300000}{5}

\Leftrightarrow x=60,000

Therefore he invested $60,000 at 9% per year and $(210,000-60,000)=$150,000 at 4% per year.

7 0
3 years ago
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