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amid [387]
3 years ago
10

Mr. Saenz earned $240 for working 3 eight hour shifts at the lumber yard. What's his hourly wage?

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0
3 shifts*8 hours each= 24 hours worked

$240/24 hours= $10 per hr

Final answer: $10 per hr
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A man sold 50 metres of cloth for Rs.5640 at a profit of 20%.
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I) 80% x 5640 = Rs. 4512
ii) 4512 divide by 50 = Rs. 90.24
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A group of friends go out to breakfast the total bill including tax is $33 with the tax on the meal is 7% and a 15% tip is left
RSB [31]
The answer is 25.74$ because 7% of the 33$ is 2.31$ and the tip which 15% is 4.95$ so if you subtract all that it come out to 25.74$
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3 years ago
Noelle used 17 lemons to make lemonade. This was 85% of all the lemons
LuckyWell [14K]

Answer:

20 lemons

Step-by-step explanation:

Let the number of lemons = 'x'

85% of x = 17

\frac{85}{100}*x = 17\\\\x = \frac{17*100}{85}\\x = 20

6 0
2 years ago
Read 2 more answers
I would like to know if 1 km is greater or less then 999 m
aleksandrvk [35]
Greater 1 km = 1000 m
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2 years ago
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3.30 Survey response rate. Pew Research reported in 2012 that the typical response rate to their surveys is only 9%. If for a pa
Artist 52 [7]

Answer:

0% probability that at least 1,500 will agree to respond

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 15000, p = 0.09

So

\mu = E(X) = np = 15000*0.09 = 1350

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{15000*0.09*0.91} = 35.05

What is the probability that at least 1,500 will agree to respond

This is 1 subtracted by the pvalue of Z when X = 1500-1 = 1499. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1499 - 1350}{35.05}

Z = 4.25

Z = 4.25 has a pvalue of 1.

1 - 1 = 0

0% probability that at least 1,500 will agree to respond

6 0
3 years ago
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