Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
do the pemdas
p=()
e=X^x
md= multiply then devide
as= add then subtract
Step-by-step explanation:
y=3x^2+9x-18
y=9x+9x-18
18x-18=y
Answer:
This is the commutative property of multiplication.
Step-by-step explanation:
We know this because that property states that it does not matter what order the numbers are multiplied together, as long as they are all being multiplied. So even though the numbers change on both sides, it does not affect the answer.
The point that passes through the line Y-5=-3(x-4) is (-4,7). You are very welcome.
