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xz_007 [3.2K]
3 years ago
7

Please help! Solve for x.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Hello

Good Luck

Goodbye ♥

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Are 6/10 and 6/30 multiples of 3/10
Fantom [35]
10 is not a multiple of 3 so no 6/10 is not multiples for 3/10 and 6 is not a mutiple of 10 so it can't be also the same with 6/30 although 6/30 is multiples for 3 but 6 is not a mutiple for 10.
7 0
4 years ago
Read 2 more answers
Imani is selling T-shirts for a student council fund-raiser. She spent $100 on
Kruka [31]

Answer:

Step-by-step explanation:

the domain is gonna be ur x values and ur range is gonna be ur r(x) values

the domain has to do with the number of t-shirts.....and it can range from 0 to 25.......so it would be written as : [0,25]...include the brackets....not parenthesis...or all whole numbers from 0 to 25

the range has to do with the money made....and it can range from : -100 to 200....so it would be written as : [ -100,200] ..use brackets and not parenthesis.

3 0
3 years ago
Write an equation in slope-intercept form for the line that passes through (2,-2) and is perpendicular to x + 5y =6
Oksana_A [137]
X + 5y = 6
5y = -x + 6
y = -1/5x + 6/5....the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the original slope and change the sign. So we flip -1/5 and make is -5/1....and we change the sign...making it 5/1 or just 5. So our perpendicular line will have a slope of 5.

y = mx + b
slope(m) = 5
(2,-2)...x = 2 and y = -2
sub and find b, the y int
-2 = 5(2) + b
-2 = 10 + b
-2 - 10 = b
-12 = b

so ur perpendicular equation is : y = 5x - 12 <=
3 0
3 years ago
In how many ways can six people sit in a six-passenger car?
nekit [7.7K]

Answer:

number of ways = 720

Step-by-step explanation:

The number of ways  six people sit in a six-passenger car is given by the number of permutations of 6 elements in 6 different positions ( seats), then

number of ways = number of permutations of 6 elements = 6! = 6 * 5 * 4 *3 * 2 * 1 = 720

Since the first person that sits can be on any of the seats , but then the second person that sits can choose any of 5 seats (since the first person had already occupied one) , the third can choose 4 ... and so on.

5 0
4 years ago
There are 10 rolls of film in a box and 3 are defective. two rolls are selected without replacement. what is the probability of
german

P(picking one defective) = 3/10
P(picking a 2nd defective) = 2/9


P(1 and 2  defective) = 3/10 x 2/9  = 6/90 = 0.066

Second method using combination:
 ³C₂ / ¹⁰C₂ = 1/15 = 0.066
4 0
3 years ago
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