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amm1812
3 years ago
7

When using color in a computer - generated presentation aids you should use?

Computers and Technology
1 answer:
Temka [501]3 years ago
6 0
<span>the answer is: the same background color on all visuals and no more than two colors for words.</span>
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____ is a style of programming that focuses on the step-by-step sequence of instructions and operations.
mario62 [17]

Answer: Algorithm

Explanation: An algorithm is a plan, a set of step-by-step instructions to solve a problem. it involves three basic building blocks to use when designing algorithms. these are.,

1. Sequencing

2. Selection

3. Iteration

7 0
3 years ago
Read 2 more answers
An anagram of a string is another string with the same characters in the same frequency, in any order. For example 'ab', 'bca, a
nlexa [21]

Answer:

from collections import Counter

def anagram(dictionary, query):

   newList =[]

   for element in dictionary:          

       for item in query:

           word = 0

           count = 0

           for i in [x for x in item]:

               if i in element:

                   count += 1

                   if count == len(item):

                       newList.append(item)

   ans = list()

   for point in Counter(newList).items():

       ans.append(point)

   print(ans)        

mylist = ['jack', 'run', 'contain', 'reserve','hack','mack', 'cantoneese', 'nurse']

setter = ['ack', 'nur', 'can', 'con', 'reeve', 'serve']

anagram(mylist, setter)

Explanation:

The Counter class is used to create a dictionary that counts the number of anagrams in the created list 'newList' and then the counter is looped through to append the items (tuple of key and value pairs) to the 'ans' list which is printed as output.

4 0
3 years ago
Please add thenodes given below to construct the AVL tree show all the necessarysteps,
Paha777 [63]

Answer:

30,33,37,18,23,34,15,38,40,17

To construct the AVL tree, follow these steps and diagrams are shown in the image:

• Add 30 to the tree as the root node. Then add 33 as the right child because of 33 is greater than 30 and AVL tree is a binary search tree.

• Then add 37 as the right child of 33. Here the balance factor of node 30 becomes 0-2 = -2, unbalanced.

Use RR rotation, make node 33 the root node, 30 as the left child of 33 and 37 as the right child of 33.

• Now add 18 as the left child of 30. And 23 as the right child of 18. Here the balance factor of 30 becomes 2-0 = 2. It’s unbalanced.

Use LR rotation, make 23 the parent of 18 and 30.  

• Now add 34 as the left child of 37 and 15 as the left child of 18. Add 38 as the right child of 37. And then add 40 as the right child of 38.

• Now adding 17 as the right child of 15 makes the tree unbalanced at 18.

Use LR rotation, make 17 as the parent of 15 and 18.

Explanation:

The balance factor of a node can be either 0,1 or -1. Else the tree is called unbalanced at the node.

If the inserted node is in the left subtree of the left subtree of the unbalance node, then perform LL rotation.

If the inserted node is in the right subtree of the right subtree of the unbalance node, then perform RR rotation.

If the inserted node is in the left subtree of the right subtree of the unbalance node, then perform RL rotation.

If the inserted node is in the right subtree of the left subtree of the unbalance node, then perform LR rotation.

7 0
3 years ago
Which of the following are not valid assignment statements? A) total = 9;
never [62]

Answer:

The correct option for the given question is option(b) i.e 72 = amount;

Explanation:

In the option(a) the total variable store the value 9 which is a valid assignment  

In the option(b) 72 is not a variable because the variable will never start with a numeric number. Therefore it is not a valid assignment statement.

In the option(c) the yourAge variable store the value of myAge variable which is a valid assignment.

So correct answer is an option(b).

7 0
3 years ago
What does the following code print?double[] myList = {1, 5, 5, 5, 5, 1};double max = myList[0];int indexOfMax = 0;for (int i = 1
Liula [17]

Answer:

This code will print: 4

Explanation:

Following is the step-by-step explanation for the given code:

  • Given is the array of data type double named myList, it has entries, 1, 5, 5, 5,5, 1:

                    double[] myList = {1, 5, 5, 5, 5, 1};

  • Now the first element of the array (1) with index 0 will be stored in the variable max (data type double).

                 double max = myList[0];  

  • A variable indexOfMax having datatype int will be initiated as 0.

                 int indexOfMax = 0;

  • Now for loop will be used to find the maximum number of the array. The variable i will be put as index for each element to compare with first element. If the checked element is greater than or equal to the integer in max, it will be replaced. So at the end the variable max will have value 5 that will be at index i = 4.

                    for (int i = 1; i < myList.length; i++)

                            { if (myList[i] >= max)

                               { max = myList[i];

  • Now the variable i that is the index for max value will be stored in the variable indexOfMax (indexOfMax = 4).

                  indexOfMax = i; }}

  • At end the value stored in variable indexOfMax will be printed, so 4 will be printed as output.

              System.out.println(indexOfMax);

i hope it will help you!

7 0
3 years ago
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