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vlabodo [156]
3 years ago
15

Subtract the polynomials: (6xy+4x−8y)−(3x+2y+7xy−4)

Mathematics
2 answers:
cricket20 [7]3 years ago
8 0

Answer:

-xy+x-10y+4

Step-by-step explanation:

Lilit [14]3 years ago
5 0

Answer:

x - 10y - xy + 4

Step-by-step explanation:

(6xy+4x−8y)−(3x+2y+7xy−4)

= 6xy+4x−8y−3x-2y-7xy+4

= 6xy-7xy+4x−3x−8y-2y+4

= x - 10y - xy + 4

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Hello,

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4 years ago
3(2x-1)=5x+3+7x I do t get this cause I’m stupid
DiKsa [7]

Answer:

x = -1

Step-by-step explanation:

Solve for x:

3 (2 x - 1) = 7 x + 5 x + 3

Grouping like terms, 7 x + 5 x + 3 = (5 x + 7 x) + 3:

3 (2 x - 1) = (5 x + 7 x) + 3

5 x + 7 x = 12 x:

3 (2 x - 1) = 12 x + 3

Expand out terms of the left hand side:

6 x - 3 = 12 x + 3

Subtract 12 x from both sides:

(6 x - 12 x) - 3 = (12 x - 12 x) + 3

6 x - 12 x = -6 x:

-6 x - 3 = (12 x - 12 x) + 3

12 x - 12 x = 0:

-6 x - 3 = 3

Add 3 to both sides:

(3 - 3) - 6 x = 3 + 3

3 - 3 = 0:

-6 x = 3 + 3

3 + 3 = 6:

-6 x = 6

Divide both sides of -6 x = 6 by -6:

(-6 x)/(-6) = 6/(-6)

(-6)/(-6) = 1:

x = 6/(-6)

The gcd of 6 and -6 is 6, so 6/(-6) = (6×1)/(6 (-1)) = 6/6×1/(-1) = 1/(-1):

x = 1/(-1)

1/(-1) = -1:

Answer: x = -1

7 0
4 years ago
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