Question

PLEASE HELP AS SOOOON AS POSSIBLE I WILL MARK BRAINLIEST TO WHOEVER CAN ANSWER FIRST

Answer 1

Answer:

$f(f(3))=156$

Step-by-step explanation:

we are given

$f(x)=x^2+x$

We can replace x

$f(f(x))=(f(x))^2+f(x)$

now, we can replace

$f(f(x))=(x^2+x)^2+x^2+x$

now, we can plug x=3

and we get

$f(f(3))=(3^2+3)^2+3^2+3$

we get

$f(f(3))=(9+3)^2+12$

$f(f(3))=(12)^2+12$

$f(f(3))=144+12$

$f(f(3))=156$

So,

$f(f(3))=156$