Percent means out of 100 so 1%=0.01
so we multiply each decimal with 100 and get the decimal
0.03 times 100=3%
0.3 times 100=30%
0.045 times 100=4.5%
0.49 times 100=49%
Answer:
Make sure you plot your points in a table and set it up on a graph
Step-by-step explanation:
Answer:
Step-by-step explanation:
<u>Probabilities</u>
The question describes an event where two counters are taken out of a bag that originally contains 11 counters, 5 of which are white.
Let's call W to the event of picking a white counter in any of the two extractions, and N when the counter is not white. The sample space of the random experience is
We are required to compute the probability that only one of the counters is white. It means that the favorable options are
Let's calculate both probabilities separately. At first, there are 11 counters, and 5 of them are white. Thus the probability of picking a white counter is
Once a white counter is out, there are only 4 of them and 10 counters in total. The probability to pick a non-white counter is now
Thus the option WN has the probability
Now for the second option NW. The initial probability to pick a non-white counter is
The probability to pick a white counter is
Thus the option NW has the probability
The total probability of event A is the sum of both
<span>33 =1, 3, 11, 33
75</span><span>=1, 3, 5, 15, 25, 75</span>
Answer:
x=133 y=-25
Step-by-step explanation:
I'll do both ways for you. So let's start with Substitution:
With the sub method, you have to set both equations equal to each other by setting them equal to the same variable. Since there is no coefficient in front of both x's in both equations, that variable will be easiest to solve for.
x + 2y = 83 & x + 5y = 8
Solve for x.
x = 83 - 2y & x = 8 - 5y
Once you have solved for x, set each equation equal to one another and solve for y now.
83 - 2y = 8 - 5y
Isolate all variables to one side:
83 = 8 - 3y
Now subtract the 8 to fully isolate the y variable:
75 = -3y
Divide by -3:
-25 = y Now that you have your first variable, plug it into one of the original equations and solve for x.
x + 2(-25) = 83
x - 50 = 83
x = 133
Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:
Put each equation on top of one another and subtract:
x + 2y = 83
- (x + 5y = 8)
The x's will cancel out:
(x - x) + (2y - 5y) = (83 - 8)
Simplify:
-3y = 75
Solve for y
y = -25
Then, plug y = -25 into one of the original equations:
x + 5(-25) = 8
Solve for x:
x - 125 = 8
x = 133
Hope this helps!
