The point
is on the graph of the equation.
Explanation:
The equation is ![2x+3y=8](https://tex.z-dn.net/?f=2x%2B3y%3D8)
We need to determine the point
is on the graph.
To determine the point
is on the graph, we need to substitute the point in the equation and find whether the LHS is equal to RHS.
Thus, substituting the point
in the equation
, we get,
![2(1)+3(2)=8](https://tex.z-dn.net/?f=2%281%29%2B3%282%29%3D8)
Multiplying the terms within the bracket, we have,
![2+6=8](https://tex.z-dn.net/?f=2%2B6%3D8)
Adding the LHS, we have,
![8=8](https://tex.z-dn.net/?f=8%3D8)
Thus, both sides of the equation are equal.
Hence, the point
is on the graph of the equation ![2x+3y=8](https://tex.z-dn.net/?f=2x%2B3y%3D8)
C,D and F are correct.
C is what you would think of when reading it, you walked 12 and walked 1/4(12) more.
12 + 12(1/4) =
12 + 3 =
15
D is equal to C when simplified,
12(1+1/4) =
12 + 3 =
15
F is the same as the D, it just simplified the numbers in the parenthesis
12(1+1/4) =
12(4/4 + 1/4) =
12(5/4) =
15
What makes no sense I don't get it what it means plus look it up if can
<span>y^2 + 5y + 6
=</span><span>(y + 2)(y + 3)
----------------------------------</span>
If the drawing of your octagon (or whatever) has been separated into triangles, and one triangle's area<span> is labeled, then you do not need to know the apothem. Just take the </span>area<span> of that one triangle, and multiply by the number of sides in the original </span>polygon<span>.</span>