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Ksenya-84 [330]
3 years ago
5

Are these correct, if not then please correct me!​

Computers and Technology
1 answer:
Tanya [424]3 years ago
5 0

Answer:

1 is incorrect, A is the whole oval. B doesn't matter.

2 is correct

3 is incorrect, the shared part belongs to A or B as well

4 is correct

5 is correct

6 is correct

7 is correct

8 is correct (compare to 3, it should be the inverse!)

9 is incorrect, only B with A excluded must be shaded

10 is incorrect, the whole of A must be included

Explanation:

If you point to any place in the picture, you must be able to evaluate the expression to "TRUE". Take number 10, if you point to the shared area of A and B, you can say "A or !B" is TRUE because you are inside A, so the expression is TRUE or FALSE which is TRUE.

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Answer:

The correct answer to the following question will be "Safe and relatively low data and voice transmission".

Explanation:

Frequently, the word narrow band corresponds to ultra-high-frequency, S and L bands where the reasonable range is restricted compared to the bands of high-frequency.

  • It is desirable throughout the extremely-high-frequency, L-, including S-bands due to the beneficial propagation characteristics of the wavelengths.
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4 0
3 years ago
_______________ is used by a hacker to mask intrusion and obtain administrator permissions to a computer.
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Answer:

Rootkit.

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4 years ago
When setting permissions on an object to Full Control, what otherpermissions does this encompass?Read, Write, Execute, and Modif
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Answer: read, write and modify

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7 0
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Now suppose there are four links between source and destination (three routers in the path between source and destination). Each
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Answer:

12.1 seconds

Explanation:

Step 1:

Assuming the following data :

N: Size of packet = 30 Mb

T: Transmission rate =  10 Mbps

C: Speed of light in copper = 2 * 10^8 m/s

L: Length of link 5000 km

Step 2:

Calculation of the Transmission delay and the Propagation Delay

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Propagation delay = \frac{length of link}{speed of light in copper} = \frac{5000*10^3}{2 * 10^8} = 0.025s

Step 3:

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The end-to-end delay = 4*(Transmission Delay+Propagation Delay) = 4*(3+0.025) = 12.1 seconds

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4 years ago
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