MS-DOS is a command-line operating system.
Therefore, the best answer is Command-line.
Answer:
class studentType: public personType
{
public:
virtual void print() = 0;
virtual void calculateGPA() = 0;
void setID(long id) {
studentId = id;
}
void setCourses(const string c[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
courses[i] = c[i];
}
}
void setGrades(const char cG[], int noOfC) {
noOfCourses = noOfC;
for (int i=0; i<noOfCourses; i++) {
coursesGrade[i] = cG[i];
}
}
long getID() {
return studentId;
}
string* getCourses() {
return courses;
}
char* getGrades() {
return coursesGrade;
}
studentType(string fName = "", string lastName = "",
long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);
private:
long studentId;
string courses[6];
char coursesGrade[6];
int noOfCourses;
};
Explanation:
Code rewritten
Using the python code we can say that it will be possible to calculate the neutrons and organize them as:
<h3>The code can be written as:</h3>
<em>def get_total_derivative(self,l_id):</em>
<em>def sigmoid(x, div = 0):</em>
<em>if div == 1: </em>
<em>return np.exp(-x) / (1. + np.exp(-x))**2.</em>
<em>if div == 2: </em>
<em>return - np.exp(x) * (np.exp(x) - 1) / (1. + np.exp(x))**3.</em>
<em>return 1. / (1. + np.exp(-x)) </em>
<em />
<em>def linear(x, div = 0):</em>
<em>if div == 1: </em>
<em>return np.full(x.shape,1)</em>
<em>if div > 2: </em>
<em>return np.zeros(x.shape)</em>
<em>return x </em>
<em />
<em />
<em />
See more about python at brainly.com/question/18502436
#SPJ1
Answer:
ENIAC, UNIVAC, EDVAC and IMB 1401 are the list of computers used in history of computer
Explanation:
hope it helps
plz make it brainliest ans
Answer:
Functions with a boolean return type.
Explanation:
If the return type is boolean, the only possible values are true or false.
