Answer:
Option D. LN=64 units
Step-by-step explanation:
step 1
Find the value of x
we know that
LN=LM+MN -----> equation A
we have
LN=12x+16
LM=10x+8
MN=5x-4
substitute the values in the equation A
12x+16=(10x+8)+(5x-4)
Solve for x
12x+16=15x+4
15x-12x=16-4
3x=12
x=4
step 2
Find the value of LN
LN=12x+16
LN=12(4)+16=64 units
Part A:
We see that this pair of equations has 1 solution. On a graph, the solutions of 2 (or more) lines is where the lines intersect. In this case, since these lines intersect 1 time, they have 1 solution.
Part B:
As previously mentioned, the solutions of multiple lines is where the lines intersect. In this case, since they intersect at (4,4), that is the solution.
Answer:
y = 2x - 19
Step-by-step explanation:
Graph the points on the table and you'll be able to see the answer. That's how I went about it.
or use m = y^2 - y^1 divided by x^2 - x^1 to find the slope, then solve for the initial value from there
Answer:
Minimum value = 2
Maximum value = 26
Lower quartile = 4
Median = 14
Upper quartile = 20.5
Step-by-step explanation:
Five number summary:
- Minimum value
- Maximum value
- Lower quartile
- Median
- Upper quartile
Assuming the stem is the tens column and the leaves are units, the data values are:
2, 2, 3, 5, 7, <u>13, 15</u>, 16, 20, 21, 24, 26
Minimum value = 2
Maximum value = 26
<u>Median</u> - middle value
As there is an even number of data values, the median is the mean of the 6th and 7th data values.
Median = (13 + 15) ÷ 2 = 14
<u>Lower quartile</u>
As there is an even number of data values, the lower quartile is the mean of the 3rd and 4th data values.
Lower quartile = (3 + 5) ÷ 2 = 4
<u>Upper quartile</u>
As there is an even number of data values, the upper quartile is the mean of the 20th and 21st data values.
Lower quartile = (20 + 21) ÷ 2 = 20.5
