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Ludmilka [50]
3 years ago
11

Investigators interested in studying the activation of apoptosis inject cytochrome c into the cytosol of two types of mammalian

cells: cells that are normal and cells in which Bak and Bax have been inactivated by mutation.
How would these cells be predicted to respond?
Biology
1 answer:
MAXImum [283]3 years ago
4 0

Answer: Both cell types will undergo apoptosis

Explanation:

cytochrome C functions in the mitochondria and plays an important role in the synthesis of Adenosine Triphosphate (ATP). When a cell receives an apoptosis stimulus Cytochrome C is released from the mitochondria into the cystol to activate caspase cascade thereby committing the cell to the death process. Cytochrome C triggers programmed cell death through apoptosis. Cytochrome C release is caused by swelling of the mitochondrial matrix.

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A digestive system is a part of the body that processes food into energy

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A propagation flat with dimensions of 18"x8"x2" has the following volume
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Explanation:

Volume = 18×8×2 =288 (units)³.

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8 0
3 years ago
Alkaptoneuria is a recessive genetic disorder found among North American populations at a frequency of about 1 in 500,000 births
Dafna11 [192]

Answer:

The correct answer is - 1/41,493

Explanation:

Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:

2pq + 2pqF.  ( where F is the inbreeding coefficient).

The frequency of the two different hoozygotes in inbred population can be calculated as:

p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.

Given: Frequency of Alkaptonuria (q 2) = 1:500, 000

=> q = 1/707

p = 706/707 ( Approx values)

solution:

Inbreeding coefficient (F) = 1/64

Therefore,

Frequency of Alkaptonuria in second cousins= q 2 + pqF

= 1/500, 000 + (706/707 x 1/707) x (1/64)

= 1/500, 000 + 1/45, 248

= 1/41,493 (approx)

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3 years ago
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