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Umnica [9.8K]
4 years ago
8

From her window 5m above the ground, Sherri spots a turtle on the ground at a 34 degree angle of depression. To the nearest tent

h of a meter, how far is the turtle from the base of the Sherri's building?
A: 7.4m
B: 4.8m
C: 4.1m
D: 3.4m
Mathematics
1 answer:
Thepotemich [5.8K]4 years ago
3 0
Let y be the distance from the turtle to the base of the building.

tan (34) = 5/y
y = 5 ÷ cos(34) 
y = 7.4m

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Answer: The distance is 7.4 meters (Answer A)
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In the following proportion, what does y equal?
netineya [11]

Y/4 = 39/30

Cross multiply:

30y = (4 x 39)

30y = 156

Divide both sides by 30:

Y = 156/30

Y = 5.2

The answer is C. 5.2

5 0
3 years ago
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Write the equation of a line that is perpendicular to y=3/2x+2 that goes through (6,-3)
scoray [572]

Answer:

y + 3 = -\frac{2}{3}(x-6)

Step-by-step explanation:

Perpendicular lines are lines which intersect at 90 degrees which have negative reciprocal slopes. The slope of the line y = 3/2x + 2 is 3/2. The slope of the line perpendicular to it will be -2/3. Substitute m = -2/3 and (6,-3) into the point slope form of a line.

y - y_1 = m(x-x_1)\\y - -3 = -\frac{2}{3}(x-6)\\y + 3 = -\frac{2}{3}(x-6)

4 0
4 years ago
On the dietitians beverage tray are 16 filled six ounce glasses. Four glasses contain prune juice and two glasses contain apple
zubka84 [21]

Answer:

\frac{5}{8}

Step-by-step explanation:

Given:

Total number of glasses = 16

Number of glasses containing prune juice = 4

Number of glasses containing apple juice = 2

To find:  fractional part of the glasses that contain beverages ( perhaps, H2O) other than prune juice and apple juice

Solution:

A fraction refers to the parts of a whole. In a fraction, a top number is the numerator, and a bottom number is the denominator.

Number of glasses that contain beverages ( perhaps, H2O) other than prune juice and apple juice = 16 - 4 - 2 = 10

Total number of glasses = 16

So,

Fractional part of the glasses that contain beverages ( perhaps, H2O) other than prune juice and apple juice = \frac{10}{16}=\frac{5}{8}

8 0
3 years ago
If n(A-B)=18,n(AuB)=70 and n(AnB)=25 then find n(B)
svp [43]

n(A-B) denotes elements which are in A but not in B

n(Au B) denotes elements in A and B

n(AnB) denotes elements that are common in A and B

Now I will add one more set

n(B-A) which denotes elements in B but not in A

So, n(AuB) = n(A-B) + n( B-A) +n(AnB)

70 = 18 +n(B-A) + 25

70 = 43 + n(B-A)

n(B-A) = 70-43

n(B-A) = 27

So, n(B) = n( B-A) + n( AnB)

= 27+25

= 52

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