The answer is 15h² + 26h - 21
<span>(5h – 3)(3h + 7) = 5h * 3h + 5h * 7 - 3 * 3h - 3 * 7 =
= 15h</span>² + 35h - 9h - 21 =
= 15h² + 26h - 21
6 times 79 = 474 so the 79th term is 474
Segment AD is 4, and segment AE is 3. This is because AB is 8, and half of 8 is 4, and then AC is 6, and half of 6 is 3.
Hi there!
4/5=0.8
0.8*55=44
Therefore, 44 of Matthew's pitches were strikes.
Hope this helps!