Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
Answer:
-12 = p
Step-by-step explanation:
Isolate the p terms on one side and the constants on the other side. Subtract 5p from both sides: 10 = p + 22. Next, subtract 22 from both sides, obtaining
-12 = p
Answer:
52.5
Step-by-step explanation:
=50+50×5%
=50+2.5
=52.5
Answer:
explain
Step-by-step explanation:
Answer:
- vertically expanded by a factor of 4
- then, translated upward 12 units
Step-by-step explanation:
If f(x) = x² and g(x) = 4x² = 4f(x), the function g(x) represents a vertical expansion of f(x) by a factor of 4.
If h(x) = g(x) +12, the function h(x) represents a translation of g(x) by 12 units upward.
Together, these transformations on f(x) are ...
- vertical expansion by a factor of 4
- translation upward by 12 units
_____
Please be aware that there are alternate transformations that will do the same thing:
h(x) = 4(f(x) +3) . . . . is a translation upward by 3, then a vertical expansion by a factor of 4
h(x) = f(2x) +12 . . . . is horizontal compression of f(x) by a factor of 2, then a translation upward by 12.