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3 years ago

Suppose Jim is going to build a playlist that contains 7 songs. In how many ways can Jim arrange the 7 songs on the playlist?

Mathematics

1 answer:

gulaghasi [49]3 years ago

6 0

Answer:

Jim can arrange the 7 songs on the playlist in 5040 different ways.

Step-by-step explanation:

Given

$Songs = 7$

Required

Ways of arrangement

Since, there is no restriction and conditions.

The songs can be arranged in

$Ways = 7!$

This is so because each song will have a distinct position:

So, we have

$Ways = 7 * 6 * 5 * 4 * 3 * 2 * 1$

$Ways = 5040$

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an ostrich egg weighs 2.9 pounds.The difference between the weight of this egg and the weight of an emu egg is 1.6 pounds.write

Alex73 [517]

Answer:

$2.9-w=1.6$

Step-by-step explanation:

Let w be weight of emu egg in pounds.

We have been given that an ostrich egg weighs 2.9 pounds.The difference between the weight of this egg and the weight of an emu egg is 1.6 pounds.

We can represent this information as:

$2.9-w=1.6$

Therefore, the equation $2.9-w=1.6$ will give us the weight of the emu egg, w, in pounds.

8 0

3 years ago

Read 2 more answers

Given h(t) = -2(t+ 5)^2 +4, find h(-8).

bekas [8.4K]

Answer:

Substitute -8 as x into the equation.

h(-8)=-2(-8+5)^2+4

h(-8)=-2(-3)^2+4

h(-8)=-2(9)+4

h(-8)=-18+4

h(-8)=-14

7 0

3 years ago

In order to answer the question correctly, please use the following image below:

Maru [420]

Answer:

see below

Step-by-step explanation:

The angle where chords cross is the average of the intercepted arcs. Here, that is ...

(37° +46°)/2 = (83°)/2 = 41.5°

Angle SUT is 41.5°.

_____

<em>Comment on the error</em>

The measure of an arc cannot be arbitrarily said to be the same as the angle where the chords cross. It will be the same if (a) the chords cross at the circle center, or (b) the opposite intercepted arc has the same measure. Neither of these conditions hold here.