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3 years ago

HELP ASAP IF I FAIL THEY WILL KICK ME OUT !! 10 points!!!

Mathematics

1 answer:

Vinil7 [7]3 years ago

8 0

Answer:

Step-by-step explanation:

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The students in a school can be arranged in 12, 15 and 18 equal rows and also into a solid square. What is the lowest number of

ASHA 777 [7]

Hello,

Let's x then number of students.

x is divisible by 12,15,18 thus by 180 (lcm)

x=180*k is a square

2²*3²*5*k= a square ==> k=5

x=180*5=900

Proof:

900/12=75

900/15=60

900/18=50

900=30²

4 0

3 years ago

Find the seventh term of the sequence given by the rule tn=-5n+2

Vladimir79 [104]

Tn=-5n+2
T(7)=5(7)+2
=-33

7 0

3 years ago

The Question Is In The Picture (Please Help Me Quick)

Elanso [62]

Answer:

y=mx+b

10=15x+B

b is whatever the number is you got to add or multiply to get the next number

Step-by-step explanation:

5 0

2 years ago

Find the length of midsegment YZ in trapezoid ABCD when A(-5,-6) B(-6,-2) C(-4,0) and D(3,2)

Luda [366]

Answer:

Option C

Step-by-step explanation:

Since, Y and Z are the midpoints of sides AB and CD of the given trapezoid.

Segment YZ will the midsegment of trapezoid ABCD.

By the theorem of midsegment,

m(YZ) = $\frac{1}{2}(AD+BC)$

By using expression for the length of a segment between two points,

Length of a segment = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between two points A(-5, -6) and D(3, 2),

AD = $\sqrt{(3+5)^2+(2+6)^2}$

AD = $\sqrt{64+64}$

AD = $\sqrt{128}$

AD = $8\sqrt{2}$

Distance between B(-6, -2) and C(-4, 0)

BC = $\sqrt{(-6+4)^2+(-2-0)^2}$

BC = $\sqrt{8}$

BC = $2\sqrt{2}$

Therefore, m(YZ) = $\frac{1}{2}(8\sqrt{2}+2\sqrt{2})$

= $\frac{1}{2} (10\sqrt{2})$

= $5\sqrt{2}$

Option C will be the answer.

7 0

3 years ago

Cual es el resultado de de esta ecuacion con valor obsoluto <br><br> | x + 1 | = | x - 5 |

Lisa [10]

Answer:

Well the absolute vaule will allways be postive. Therefore the answer being 2. I Think.

Step-by-step explanation:

6 0

3 years ago