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mash [69]
3 years ago
7

Highest/greatest common factor of 50 and 125

Mathematics
2 answers:
mel-nik [20]3 years ago
6 0
25 is the gratest common factor of 50 and 125
Nata [24]3 years ago
5 0
50 =2×5×5 125=5×5×5 Hoghest common factor = 5×5 =25
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What is the quotient of -3/8 and -1/3 <br> O -1 1/8<br> O -1/8<br> O 1/8<br> O 1 1/8
Nat2105 [25]
The quotient of -3/8 and -1/3 is 1 1/8.
3 0
3 years ago
15. Which of the following statements is true? a. If the calculated value of F statistic is higher than the critical value, we r
quester [9]

Answer:

c) is true

Step-by-step explanation:

Given are four statements. Let us check one by one

a) If the calculated value of F statistic is higher than the critical value, we reject the alternative hypothesis in favor of the null hypothesis

False, we reject H0 in favour or alternate

b) The F statistic is always nonnegative as SSRr is never smaller than SSRur.

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c) Degrees of freedom of a restricted model is always less than the degrees of freedom of an unrestricted model.

This is true because in a restricted we put constraints thus df will be less

d) The F statistic is more flexible than the t statistic to test a hypothesis with a single restriction.

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4 0
3 years ago
Solve the system by substitution.<br> 10x + 5y = -50<br> y = -x
Pie

Answer:

(1,-12)

Step-by-step explanation:

-10+5y=-50

5y=-60

y=-12

10x-60=-50

10x=10

x=1

8 0
3 years ago
Find the area (shaded) and round to the tenths place if necessary.
fomenos

Answer:

9π - 9

Step-by-step explanation:

Depends on what the question stated was pi (π). The area of the circle is 9(3 squared) * π. the shaded area is the area of the circle - the area of the triangle. The area of the triangle is base * high / 2. If the diameter of the circle (6) is what we use as the base, then 3 would be the high, making the area 9. This means the shaded area would be 9π - 9.

6 0
3 years ago
Find the value of 10% of Rs. 25​
VARVARA [1.3K]

Answer:

2.5 is the awnser

Step-by-step explanation:

25 divided by 10 is 2.5

8 0
3 years ago
Read 2 more answers
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