Two resistors have the values as given, R1 = 110Ω, and R2 = 560Ω. Find the equivalent resistance when the two resistors are in s
eries and when the two resistors are in parallel.
1 answer:
Answer: SERIES = 670 Ω
PARALLEL = 91.94 Ω
Step-by-step explanation:
Hi, resistors in series obey the following equation :
R1+ R2 = RT
RT is the equivalent resistance. We have the value of both resistances, so we apply the ecuation:
R1 = 110Ω, and R2 = 560Ω
110Ω+ 560Ω = 670 Ω
When resistors are in parallel, resistors obey the following equation:
1/R1 + 1/R2= 1/RT
so, in our case:
1/ 110Ω +1/560Ω = 1/rt
0.01087Ω = 1/RT
RT= 1/0.01087 Ω= 91.94 Ω
You might be interested in
Answer:
905
Step-by-step explanation:
arithmetic sequence are in form
a(n)=a(0)+d(n-1)
a(0)=25
common difference: d=35-25=10
a(n)=25+10(n-1)
a(89)=25+10(88)=905
C. cannot because the letters representing them are not the same
What are the possible answers?
Answer:
The area is 3.14
Step-by-step explanation:
Get the radius and times it by itself then multiply it by pie and you get 3.14
1 over m to the 2 power: 1/m^2
