Two resistors have the values as given, R1 = 110Ω, and R2 = 560Ω. Find the equivalent resistance when the two resistors are in s
eries and when the two resistors are in parallel.
1 answer:
Answer: SERIES = 670 Ω
PARALLEL = 91.94 Ω
Step-by-step explanation:
Hi, resistors in series obey the following equation :
R1+ R2 = RT
RT is the equivalent resistance. We have the value of both resistances, so we apply the ecuation:
R1 = 110Ω, and R2 = 560Ω
110Ω+ 560Ω = 670 Ω
When resistors are in parallel, resistors obey the following equation:
1/R1 + 1/R2= 1/RT
so, in our case:
1/ 110Ω +1/560Ω = 1/rt
0.01087Ω = 1/RT
RT= 1/0.01087 Ω= 91.94 Ω
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