Length of deck is 40 feet
<h3><u><em>Solution:</em></u></h3>
Sam wants the deck to have an overall perimeter of 60 feet
Perimeter of rectangular deck = 60 feet
Let "L" be the length of rectangle and "W" be the width of rectangle
Given that plans for a rectangular deck call for the width to be 10 feet less than the length
Width = length - 10
W = L - 10 ------ eqn 1
<em><u>The perimeter of rectangle is given as:</u></em>
perimeter of rectangle = 2(length + width)
Substituting the known values we get,
60 = 2(L + L - 10)
60 = 2(2L - 10)
60 = 4L - 20
80 = 4L
L = 20
Thus the length of deck is 20 feet
Answer: 1:15pm
Step-by-step explanation:
For this case, the main function is given by:
We can apply the following transformation:
Horizontal displacements:
Assume h> 0:
To graph f (x + h) move the graph of f (x) h units to the left.
For h = 1 we have:
Answer:
the graph y=6(x+1)^2 is the graph y=6x^2 moved 1 unit to the left.
If x is length of the diagonal then
x^2 = 3^2 + 4^2 = 25
x = sqrt25 = 5
Diagonal is 5 units long
