Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
The cross-section of a square pyramid will be a square. The section above the cross-section taken will basically be a similar but smaller square pyramid. D is the correct answer.
The solution to the system of equation is (1, 4).
In order to find this, we can first just see where the graphs intersect each other. This will give us the solution set.
As for what it represents, the x value in the increase in temperature and the y value is the increase in customers.
Therefore, we know that we want the temperature to go up by 1 (although we don't know the units) and that would result in the amount of people coming, and staying longer by 4 (again, we don't know the units of measure).
10xBx15+11xB is that what you are needing for the answer because you didn't really say what you where looking for.
I believe it is a rational number
