Answer: There is a 50% chance that the offspring will inherit Huntington's disease
Explanation:
Huntington's disease is expressed by a dominant allele.
Since the father is heterozygous for Huntington's disease, his genotype would be as follows:Hh
Even though he carries a normal allele, the dominant allele is disease causing and thus masks the effects of the normal allele, therefore he expresses the disease.
The mother does not have Huntington's because she is homozygous recessive, in other words, she carries 2 copies of the normal alleles.with the genotype hh.
If you do a punnet square, and you cross the mother and father, the following genotypes can be produced:
Hh, Hh, hh, hh
Therefore, there's a 50% chance that the offspring will inherit the disease causing allele and 50% chance that the offspring will not inherit it.
It’s A an generation that’s the only one that makes sense because evolution is a change over time too
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From DNA to RNA, purines and pirimidines transform in this matter:
(A) adenine => (U) uracile ; because RNA has uracile instead of timine in DNA
(G) guanine => (C) citosine
mRNA: G U G C A C C U G A C U C C U G A G G A G
GUG-valine
CAC-histidine
CUG-leucine
ACU-threonine
CCU-proline
GAG-glutamic acid
GAG-glutamic acid
Hope this helps!
