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3 years ago

(6×5)×_=300 complete the pattern

Mathematics

1 answer:

Verdich [7]3 years ago

8 0

(6×5)×10=300 Since 6×5=30×10=300

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The product of x and 3

Ne4ueva [31]

Answer:

3x- we need to know what x is to go any further

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Can you guys help me with this problem, please I need it right now.

7nadin3 [17]

In the graph, the constant of proportionality is 40

<h3>Calculating the constant of proportionality</h3>

From the question, we are to determine the constant of proportionality

The constant of proportionality = $\frac{y}{x}$

From the graph, a point on the line is (1, 40)

That is,

When x = 1 and y = 40

Thus,

The constant of proportionality = $\frac{40}{1}$

Constant of proportionality = 40

Hence, the constant of proportionality is 40

Learn more on Constant of proportionality here: brainly.com/question/11391605

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3 0

2 years ago

Kevin and Randy Muise have a jar containing 92 coins, all of which are either quarters or nickels. The total value of the coins

Artemon [7]

<span>Let n = the number of nickles
Let q = the number of quarters
Then for your problem we have
(1) n + q = 43 and
(2) 5*n + 25*q = 100*6.95 (always work in cents to avoid decimal numbers) or
(3) 5*n + 25*q = 695
Now substitute n of (1) into (3) and get
(4) 5*(43 - q) + 25*q = 695 or
(5) 215 - 5*q + 25*q = 695 or
(6) 20*q = 695 - 215 or

(7) 20*q = 480 or
(8) q = 24
Then using (1) we get
(9) n + 24 = 43 or
(10) n = 19
Let's check these values.
Is (.05*19 + .25*24 = 6.95)?
Is (.95 + 6.00 = 6.95)?
Is (6.95 = 6.95)? Yes
Answer: Kevin and Randy have 19 nickles and 24 quarters in the jar.</span>

7 0

3 years ago

I need help from uh all..

DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

$\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})$

To prove this identity we will take the right side of the identity,

$\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})$

$=\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})$

$=\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]$

$=\frac{1}{2}(\frac{2}{\text{tan}A} )$ [Since $\text{tan}A=\frac{2\text{tan}\frac{A}{2}}{1-\text{tan}^2\frac{A}{2}}$ ]

= cot A

Hence right side of the equation is equal to the left side of the equation.

3 0

3 years ago

100 point reward with certified answer. 4 basic algebra questions, must show work. If the answers are wrong your response will b

ipn [44]

Y=kx
12=-4k
k = -3

so when y = 15
y = kx
15 = -3x
x = -5

----------------

$50 / 0.04 = $1250 (4% interest)

so
1250 * 0.06 = $75

answer
interest $75 at 6%

-----------------------------

y = kx
1/4 = 4k
k = 1/16

when x = 5
y = kx
y = 1/16(5)
y = 5/16

-----------
y = kx
-5 = 4k
k = -5/4

direct equation
y = -5/4x

6 0

3 years ago