Option A. All the real values of x where x < -1
Procedure
Solve the inequality:
(x -3)(x+1)>0
That happens in two cases.
1) When both factors >0
x-3>0 and x+1>0
x>3 and x >-1
The intersection is x >3
2) When both factors <0
x-3<0 and x+1<0
x<3 and x<-1
the intersection is x<-1.
We have obtained that the function is positive for the intervals x < -1 and x > 3. But in one of those intervals the function is decresing and in the other is increasing.
You can recognize that the function given is a parabola and, because the coefficient of the quadratic term is positive, the parabola opens upward. Then the function is decreasing in the first interval and increasing in the second interval.
Answer:
whats the question ??
Step-by-step explanation:
Answer:
-1/8
Step-by-step explanation:
Perpendicular slopes are negative reciprocals
The slope of y=8x+5 is 8, because it is in slope intercept form: y=mx+b form, where m is the slope.
Negative:
8/1--> -8/1
Reciprocal:
Flip the numerator and denominator
-8/1--> -1/8
So, the perpendicular slope of 8 is -1/8
Answer:
√124 simplifies to 2√31 ≈ 11.135529
Step-by-step explanation:
√124 = √(4·31) = (√4)(√31) = 2√31
A calculator can tell you the numerical value. It is an irrational number near ...
11.135528725660043844...
Domain (the range of x values)
Range (the range of the y values)
Domain: (-9, 11)
Range: (-4, 6)
